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liq [111]
3 years ago
6

Solve 2x2 + 20x = −38.

Mathematics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

Correct Answer is C(−5 ±square root 6)

Step-by-step explanation:

2x^2+20x+38=0

2(x^2+10x+19)=0

x^2+10x+19=0

This is a quadratic equation here we have used following formula to find the roots of this equation

x=-b−±square root (b^2-4*a*c))/2*a......(1)

Here,

a=1

b=10

c=19

put values of a, b and c in equation (1)

x=(-10 ±square root(10^2-4*1*19))/2*1

x=(-10 ±square root(100-76))/2

x=(-10 ±square root(24))/2

x=(-10 ±square root(2*2*6))/2

x=(-10 ±2square root(6))/2

x=2(-5 ±square root(6))/2

x=-5 ±square root(6)


Hope this answer will help you

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