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3 years ago

Eleven is 20% of ____

Mathematics

2 answers:

FrozenT [24]3 years ago

7 0

Hey!

11 = 20% of <u>55</u>

You can make a proportion

20% = 20/100

$\frac{20}{100} = \frac{11}{y}$

Cross multiply

$100 \times 11 = 1,100$

Divide by 20

$1,100 \div 20 = 55$

$\framebox{Answer = 55}$

ollegr [7]3 years ago

5 0

Convert to a decimal which would be 0.55 (11/20).

Then you want to multiply 0.55 by 100 (which is a whole number, all % is going to come from 100) to convert to a full % -> 0.55*100

Then you will simplify 0.55*100

You answer will be 55%.

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Question

meriva

Question:

In a neighbourhood pet show, each of the animals entered is equally likely to win. if there are 7 dogs, 6 cats, 3 birds, and 2 gerbils entered, what is the probability that a bird will win the top prize?

Answer:

Probability that a bird will win the top prize is 0.167

Step-by-step explanation:

Given:

The number of dogs = 7

The number of cats = 6

The number of birds = 3

The number of gerbils = 2

To Find:

Probability that a bird will win the top prize = ?

Solution:

Let us first find the total number of pets .

The Total number of pets = 7 + 6 + 3 + 2 = 18

Now the probability of a bird will win the top prize is

=> $\frac{\text {Number of birds}}{\text{ Total number of pets}}$

=> $\frac{3}{18}$

=> $\frac{1}{6}$

=>0.167

4 0

3 years ago

Jenny makes quilts. she can make 7 quilts with 21 yards of material. how many yards of material would be required to make 12 qui

kozerog [31]

3 yards per quilt

36 for 12

8 0

3 years ago

Read 2 more answers

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.