PLEASE HELP MEEE

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

2x^3 + 9x^2 + 16x + 21.

Step-by-step explanation:

We first multiply the expression in the second parentheses by x , then by +3:

(x + 3)(2x^2 + 3x + 7)

= x(2x^2 + 3x + 7) + 3(2x^2 + 3x + 7)

= 2x^3 + 3x^2 + 7x + 6x^2 + 9x + 21 Now we add like terms:

= 2x^3 + 9x^2 + 16x + 21.

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What value of n makes the equation true? (2x^9y^n)(4x^2y^10)=8x^11y^20

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Hi there! The answer is n = 10.

$(2 {x}^{9} {y}^{n} )(4 {x}^{2} {y}^{10} ) = 8 {x}^{11} {y}^{20}$

As you see at the powers of x, we need to add the exponents of the power we when multiply them.
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4 years ago

Natalie had 64 beads. She used 24 beads to make a bracelet. She used 7/8 of the remaining beads to make a necklace. How many bea

Eddi Din [679]

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Natalie have left with 5 beads.

Step-by-step explanation:

Given:

Natalie had 64 beads. She used 24 beads to make a bracelet. She used 7/8 of the remaining beads to make a necklace.

Now, to find the beads does Natalie have left.

Total beads Natalie had = 64 beads.

And beads she used to make a bracelet = 24 beads.