Answer: the mass of a neutron is approximately 2,000 times the mass of an electron
Step-by-step explanation:
- the easiest way to solve this (in my opinion) is to simply divide the mass of a neutron by the mass of an electron
- ![2 x10^{-24} / (9 x10^{-28} )](https://tex.z-dn.net/?f=2%20x10%5E%7B-24%7D%20%2F%20%289%20x10%5E%7B-28%7D%20%29)
= ![(2/9) x10^{-24--28}](https://tex.z-dn.net/?f=%282%2F9%29%20x10%5E%7B-24--28%7D)
= ![(2/9)x10^{-24+28}](https://tex.z-dn.net/?f=%282%2F9%29x10%5E%7B-24%2B28%7D)
≈ ![0.2222x10^{28-24}](https://tex.z-dn.net/?f=0.2222x10%5E%7B28-24%7D)
≈ ![0.2222x10^{4}](https://tex.z-dn.net/?f=0.2222x10%5E%7B4%7D)
≈ which is approximately 2222
- so 2222 is approximately 2000 times
- therefore, the mass of a neutron is approximately 2,000 times the mass of an electron
hope this helps :)
Answer:
Option A. ![40\ cm](https://tex.z-dn.net/?f=40%5C%20cm)
Step-by-step explanation:
we know that
The lateral area of a cone is equal to
![LA=\pi rl](https://tex.z-dn.net/?f=LA%3D%5Cpi%20rl)
we have
![LA=400\pi \ cm^{2}](https://tex.z-dn.net/?f=LA%3D400%5Cpi%20%5C%20cm%5E%7B2%7D)
![r=10\ cm](https://tex.z-dn.net/?f=r%3D10%5C%20cm)
substitute and solve for l (slant height)
![400\pi=\pi (10)l](https://tex.z-dn.net/?f=400%5Cpi%3D%5Cpi%20%2810%29l)
simplify
![400=(10)l](https://tex.z-dn.net/?f=400%3D%2810%29l)
![l=400/10=40\ cm](https://tex.z-dn.net/?f=l%3D400%2F10%3D40%5C%20cm)
person number 60
10 20 30 40 50<u> 60</u>
12 14 36 48<u> 60</u>
It id in both of their times tables.<u />
"fifty thousand six hundred and seventy nine" and 50,000 + 600 + 70 + 9
Answer:
Should be 530.55 total that week
And 80.55 in commissions