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topjm [15]
3 years ago
14

I need help with this question

Mathematics
1 answer:
alex41 [277]3 years ago
7 0
Since the triangle is cut in half, I’m guessing it’s 22.5
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One of the legs of a right triangle measures 2 cm and the other leg measures 15 cm. Find the measure of the hypotenuse. If neces
mash [69]

Answer:

c = 15.1

Step-by-step explanation:

Formula:

a² + b² = c²

15² + 2² = c²

225 + 4 = c²

229 = c²

\sqrt{c^2} =\sqrt{229}

c = 15.1

3 0
3 years ago
-----100PTS-----PLZ HURRY 1-The letters from the word FOOTBALL are written on 8 cards with one letter on each card. One card wil
SCORPION-xisa [38]
10/13 gbbhabvwjwhw cub wbqhwnnegegehqjq
6 0
3 years ago
How do i find the circumcenter of a triangle with an undefined slope
gulaghasi [49]

The slope perpendicular to an undefined slope is: 0

Example:

x = 5 is a vertical line and has an undefined slope.

The line perpendicular to it is y = <em>any value</em> which has a slope of 0.


I hope this makes sense.  If not, please post the homework question so we can help you find the circumcenter.

3 0
3 years ago
The total lateral surface area and the total surface area.
goldfiish [28.3K]
The total lateral surface area
 This is the area of the sides of the figure. In this case it will be the sum of the three rectangles.
 (13) * (14) + (13) * (14) + (14) * (10) = 504yd ^ 2
 the total surface area.
 This is the surface area of the whole figure. In this case there are three rectangles and two triangles.
 (13) * (14) + (13) * (14) + (14) * (10) + (1/2) * (10) * (12) + (1/2) * (10) * (12 ) = 624 yd ^ 2
 the answer is
 total lateral surface area: 504yd ^ 2
 total surface area: 624 yd ^ 2
3 0
4 years ago
Read 2 more answers
Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2
ankoles [38]

Option C:

2 g^{3}-5 g^{2}+6

Solution:

Given expression:

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

To find which expression is equal to the given expression.

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

Expand the term -\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12

         $=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}

Arrange the like terms together.

         $=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}

         $=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}

Factor the numerator 2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)

         $=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}

Cancel the common factor g + 2, we get

         =2 g^{3}-5 g^{2}+6

Hence option C is the correct answer.

8 0
3 years ago
Read 2 more answers
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