Answer:
0.67 cm/s
Step-by-step explanation:
The area of a square is given by :
....(1)
Where
x is the side of a square
![\dfrac{dA}{dt}=12\ cm^2/s](https://tex.z-dn.net/?f=%5Cdfrac%7BdA%7D%7Bdt%7D%3D12%5C%20cm%5E2%2Fs)
Differentiating equation (1) wrt t.
![\dfrac{dA}{dt}=2x\times \dfrac{dx}{dt}](https://tex.z-dn.net/?f=%5Cdfrac%7BdA%7D%7Bdt%7D%3D2x%5Ctimes%20%5Cdfrac%7Bdx%7D%7Bdt%7D)
When A = 81cm², the side of the square, x = 9 cm
Put all the values,
![12=2\times 9\times \dfrac{dx}{dt}\\\\\dfrac{dx}{dt}=\dfrac{2}{3}\\\\\dfrac{dx}{dt}=0.67\ cm/s](https://tex.z-dn.net/?f=12%3D2%5Ctimes%209%5Ctimes%20%5Cdfrac%7Bdx%7D%7Bdt%7D%5C%5C%5C%5C%5Cdfrac%7Bdx%7D%7Bdt%7D%3D%5Cdfrac%7B2%7D%7B3%7D%5C%5C%5C%5C%5Cdfrac%7Bdx%7D%7Bdt%7D%3D0.67%5C%20cm%2Fs)
So, the length of the side of a square is changing at the rate of 0.67 cm/s.
Answer: The standard form of an equation is Ax + By = C. In this kind of equation, x and y are variables and A, B, and C are integers.
Explanation:
We can convert a point slope equation into standard form by moving the variables to the left side of the equation.
Answer: B
Step-by-step explanation:
Beth's description of the transformation is incorrect
<h3>Complete question</h3>
Beth says that the graph of g(x)=x-5+1 is a translation of 5 units to the left and 1 unit up of f(x) = x. She continues to explain that the point (0,0) on the square root function would be translated to the point (-5,1) on the graph of g(x). Is Beth's description of the transformation correct? Explain
<h3>How to determine the true statement?</h3>
The functions are given as:
g(x) = x - 5 + 1
f(x) = x
When the function f(x) is translated 5 units left, we have:
f(x + 5) = x + 5
When the above function is translated 1 unit up, we have:
f(x + 5) + 1 = x + 5 + 1
This means that the actual equation of g(x) should be
g(x) = x + 5 + 1
And not g(x) = x - 5 + 1
By comparison;
g(x) = x - 5 + 1 and g(x) = x + 5 + 1 are not the same
Hence, Beth's description of the transformation is incorrect
Read more about transformation at:
brainly.com/question/17121698
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We have to find the domain of y = cotx
We know that cotx = cos
x / sinx
And also when sinx becomes zero cotx becomes undefined
And again we know that value of cosx and sinx can be between -1 to 1
But value of cotx can lie in between -∞ to +∞
Just for example cot30 is cos30 / sin30
= √3/2/1/2 = √3
Therefore domain of cotx is x
x ∈ R , x ≠ πn for any integer n