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Step2247 [10]
3 years ago
10

10% of 40.5 is what number

Mathematics
1 answer:
pav-90 [236]3 years ago
6 0
You have to calculate it and the answer is 24.69
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9. A rectangular garden has a length that is 3 feet longer than its width. Let w represent the width of the garden, in feet. The
inysia [295]

Answer:

B

Step-by-step explanation:

w=width

l=w+3

(w+4)=width+walkway(both sides)

(w+7)=length+walkway(both sides)

7 0
3 years ago
Determine which of the following sets of ordered pairs represents a function
Illusion [34]

Answer:

B.

Step-by-step explanation:

Every answer besides B. has an input that repeats. A function contains inputs that have exactly one output. This means x values cannot have more than one y value.

8 0
3 years ago
Use the distance formula to calculate the length of the leg CD
Karo-lina-s [1.5K]

To calculate the distance between two points on the coordinate system you have to use the following formula:

d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}

Where

d represents the distance between both points.

(x₁,y₁) are the coordinates of one of the points.

(x₂,y₂) are the coordinates of the second point.

To determine the length of CD, the first step is to determine the coordinates of both endpoints from the graph

C(2,-1)

D(-1,-2)

Replace the coordinates on the formula using C(2,-1) as (x₁,y₁) and D(-1,-2) as (x₂,y₂)

\begin{gathered} d_{CD}=\sqrt[]{(2-(-1))^2+((-1)-(-2))}^2 \\ d_{CD}=\sqrt[]{(2+1)^2+(-1+2)^2} \\ d_{CD}=\sqrt[]{3^2+1^2} \\ d_{CD}=\sqrt[]{9+1} \\ d_{CD}=\sqrt[]{10} \end{gathered}

The length of CD is √10 units ≈ 3.16 units

6 0
1 year ago
What is the mixed number form<br> of 33/8
goblinko [34]
HCF of 8 that will go as much as possible to 33

4*8=32 and denominator is 8

33-32=1 which is the numerator

Answer is :

4 1/8
4 0
3 years ago
Read 2 more answers
Cassie rolls a fair number cube with 6 faces labeled 1 through 6 she rolls the number cube 300 times which results is most likel
ollegr [7]
It depend upon what you roll it could be 6 because there are 6 faces are the dice 
3 0
3 years ago
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