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Anna71 [15]
3 years ago
6

Martha has widow's peak and attached earlobes. Martha's dad had a straight hairline and unattached earlobes. If Martha marries a

man that is heterozygous for both traits, what is the probability that they will have a child with a widow's peak and attached earlobes?
Mathematics
1 answer:
krok68 [10]3 years ago
6 0

Answer:

the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%

Step-by-step explanation:

Martha = widow's peak + attached earlobes.

Martha's dad = straight hairline + unattached earlobes.

Martha husband =straight hairline+ widow's peak + attached earlobes

what is the probability that Martha child will have a widow's peak + attached earlobes?

since,

Martha + Martha husband =straight hairline+ widow's peak + attached earlobes

the probability of the child having widow peak is 2/3 = 0.6667

the probability of the child having attached earlobes is 2/3 = 0.66667

the probability of having both = 0.6667*0.66667 = 0.4445

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Step-by-step explanation:

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Answer:

Range: (844.9,1333.7)

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Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1083.9 cm cubed

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Range rule thumb:

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Upper Limit:

\mu + 2\sigma = 1089.3 + 2(122.2) = 1333.7

Lower limit:

\mu - 2\sigma = 1089.3 - 2(122.2) = 844.9

Since, 1348.3 does not lie in the range (844.9,1333.7),  a brain volume of 1348.3 cm cubed can be considered significantly high.

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