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2 years ago

You bought a magazine for $3 and some

Mathematics

2 answers:

Anni [7]2 years ago

4 0

Answer: 8 candy bars

if i can have brainliet that would be great

Step-by-step explanation:

Transform the question to an equation:

3 + 2x = 19

Solve:

2x = 16

x = 8

Check the answer:

3 + 2 (8) = 19

3 + 16 = 19

True

Anon25 [30]2 years ago

4 0

Answer: 8 candy bars

Step-by-step explanation:

Bought a magazine $3

Now you have 16$

2$ a candy bar times 8 is 16$

You might be interested in

F(x) = 5x3 + 2x2 – 7x + 4 g(x) = 3x – 7 Find (f + g)(x).

grin007 [14]

Step-by-step explanation:

5x^3+2x^2-4x-3

option b is correct answer

hope it helps you

3 0

3 years ago

Sam takes out a $167,000 mortgage for 20 years. He makes monthly payments and at the end calculates

cupoosta [38]

Answer:

The Annual rate of interest for the mortgage is 1.8%

Step-by-step explanation:

Given as :

The mortgage principal = p = $167,000

The time period of mortgage = t = 20 years

The Amount paid towards mortgage in 20 years = A = $240,141

Let the Annual percentage rate on interest = r % compounded annually

Now, From Compound Interest method

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, $240,141 = $167,000 × $(1+\dfrac{\textrm r}{100})^{\textrm 20}$

or, $\dfrac{240,141}{167,000}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 20}$

Or , 1.437 = $(1+\dfrac{\textrm r}{100})^{\textrm 20}$

Or, $(1.437)^{\frac{1}{20}}$ = $(1+\dfrac{r}{100})$

or, 1.018 = $(1+\dfrac{r}{100})$

Or, $\dfrac{r}{100}$ = 1.018 - 1

Or, $\dfrac{r}{100}$ = 0.018

∴ r = 0.018 × 100

i.e r = 1.8

So, The rate of interest applied = r = 1.8 %

Hence, The Annual rate of interest for the mortgage is 1.8% Answer

8 0

3 years ago

A large manufacturing firm tests job applicants who recently graduated from college. The test scores are normally distributed wi

Sergeeva-Olga [200]

Answer:

The lowest score a college graduate must be 577.75 or greater to qualify for a responsible position and lie in the upper 6%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 50

We are given that the distribution of test score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.06.

P(X > x) = 6% = 0.06

$P( X > x) = P( z > \displaystyle\frac{x - 500}{50})=0.06$

$= 1 - P( z \leq \displaystyle\frac{x - 500}{50})=0.06$

$=P( z \leq \displaystyle\frac{x - 500}{50})=1-0.06=0.94$

Calculation the value from standard normal z table, we have,

$P(z < 1.555) = 0.94$

$\displaystyle\frac{x - 500}{50} = 1.555\\x = 577.75$

Hence, the lowest score a college graduate must be 577.75 or greater to qualify for a responsible position and lie in the upper 6%.

5 0

3 years ago

STRUGGLING, please help! Need help with a math problem. ty

strojnjashka [21]

f(3) = 7(3) - 6

g(2) = 3(2)

f(3) = 15

g(2) = 6

15 - 6 = 9

5 0

3 years ago

Me puede ayudar con esto porfa.

dsp73

Answer:

La respuesta correcta es la opción d) 5 a 1.

Step-by-step explanation:

Para calcular la relación entre los ingresos de Mary en 2019 ( $I_{2019}$ ) con respecto a sus ingresos en 2018 ( $I_{2018}$ ), partimos de que los ingresos de Mary en 2019 fueron un 20% mayores que sus ingresos en 2018:

$I_{2019} = 20\% \: I_{2018}$

$I_{2019} = \frac{20}{100}I_{2018}$

$\frac{100}{20}I_{2019} = I_{2018}$

$5I_{2019} = I_{2018}$

Entonces, la relación entre los ingresos de Mary en 2019 es 5 veces los ingresos de Mary en 2018. Por lo tanto, la respuesta correcta es la opción d) 5 a 1.

Espero que te sea de utilidad!

4 0

3 years ago