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3 years ago

For the function y=8−5x, what is the ordered pair when x=7?

Mathematics

2 answers:

zzz [600]3 years ago

5 0

Answer:

Ordered pairs are (0,7) , (1,8) , (-1,6) and (-7,0)

Step-by-step explanation:

ivolga24 [154]3 years ago

3 0

Answer:

(7, -27)

Step-by-step explanation:

Given y=8-5x and x=7,

We substitute x=7 into the equation y=8-5x.

This would give us y= 8-5(7) and can be further sinplified to y= 8-35 = -27.

Ordered pair refers to 2 numbers that come in a pair to fulfil an equation in the form of (x, y).

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hoa [83]

Step-by-step explanation:

you just substitute (-2) into the x values of the above function

$f( - 2) = - 4( - 2)^{2} - 9( - 2) + 20 \\ f( - 2) = 22$

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3 years ago

5x-1/5=7/3 <br> Find The LCD That would eliminate the fractions

photoshop1234 [79]

Answer:

$x=\frac{7}{15}$

Step-by-step explanation:

$5x-\frac{1}{5} =\frac{7}{3}$

$5x - \frac{3}{15} = \frac{35}{15}$

$5x - \frac{3}{15} + \frac{3}{15} = \frac{35}{15} + \frac{3}{15}$

$5x=\frac{35}{15}$

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3 years ago

What is the product?

svlad2 [7]

Answer:

Third option: 2x^3-11x^2+16x-3

Step-by-step explanation:

The product to be found is:

$(x-3)(2x^2-5x+1)$

Distributive property will be used for the product:

$x(2x^2-5x+1)-3(2x^2-5x+1)\\$

Multiplication will give us:

$=2x^3-5x^2+x-6x^2+15x-3\\Combining\ alike\ terms\\=2x^3-5x^2-6x^2+x+15x-3\\=2x^3-11x^2+16x-3$

The product is: 2x^3-11x^2+16x-3

Hence, third option is the correct answer ..

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