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FrozenT [24]
3 years ago
6

How can you express (32+56) as a multiple of a sum of whole numbers with no common factor

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
4 0
44X 2 is the same thing is that what your asking am a little confused

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What is the area of a trapezoid with bases of 15.8 yd and 21.8 yd and a height of 11.7 yd?
DedPeter [7]

Add the bases together, divide that by 2 then multiply by the height.

15.8 + 21.8 = 37.6

37.6/2 = 18.8

18.8 x 11.7 = 219.96 yd^2

3 0
3 years ago
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What is 9/10 minus 3/5
madam [21]
9/10

3/5 *2/2 +6/10

9/10-6/10=3/10 or .3
8 0
3 years ago
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A suspension bridge has two main towers of equal height. A visitor on a tour ship
Scilla [17]

Answer:

The Height of the tower is 188.67 ft

Step-by-step explanation:

Given as :

The angle of elevation to tower = 15°

The distance travel closer to tower the elevation changes to 42° = 497 ft

Now, Let the of height of tower = h  ft

The distance between 42°  and  foot of tower = x  ft

So, The distance between 15° and  foot of tower =  ( x + 497 )  ft

So, From figure :

<u>In Δ ABC </u>

Tan 42° = \frac{perpendicular}{base}

Or , Tan 42° = \frac{AB}{BC}

Or,  0.900 = \frac{h}{x}

∴ h = 0.900 x

Again :

<u>In Δ ABD </u>

Tan 15° = \frac{perpendicular}{base}

Or , Tan 15° = \frac{AB}{BD}

Or,  0.267 = \frac{h}{( x + 497 )}

Or,  h = ( x + 497 ) × 0.267

So, from above two eq  :

     0.900 x =  ( x + 497 ) × 0.267  

Or, 0.900 x - 0.267 x =  497  × 0.267  

So, 0.633 x = 132.699

∴               x = \frac{132.699}{0.633}

Or,            x = 209.63  ft

So, The height of tower = h = 0.900 × 209.63

Or,                                      h = 188.67 ft

Hence The Height of the tower is 188.67 ft    Answer

3 0
3 years ago
Lim 1 + cos TX<br>5.<br>x&gt;1 tanưrex​
Brums [2.3K]

Answer: 1/2

\lim_{x \to 1}\frac{1+cos \pi x}{tan^{2}\pi x }\\\\ = \lim_{x \to 1} \frac{1+cos\pi x}{\frac{sin^{2}\pi x }{cos^{2}\pi x } } \\\\\\= \lim_{x \to 1}\frac{cos^{2}\pi x(1+cos\pi x) }{sin^{2}\pi x } \\\\\\= \lim_{x \to 1} \frac{cos^{2}\pi x(1+cos\pi x)}{1-cos^{2}\pi x }  \\\\= \lim_{x \to 1} \frac{cos^{2}\pi x }{1-cos\pi x} \\\\= \lim_{x \to 1}\frac{cos^{2}\pi .1 }{1-cos\pi .1}\\\\= \lim_{x \to 1}\frac{1}{1-(-1)}\\\\=\frac{1}{2}

Step-by-step explanation:

5 0
2 years ago
If the diagonal of a square is 12 centimeters, the area of the square is
galina1969 [7]
My answer of the square is 72
8 0
3 years ago
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