Complete the remainder of the table for the given function rule:
1 answer:
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Answer:
(- ,
)
Step-by-step explanation:
Given the2 equations
6 - 2x = y → (1)
14 + 3x = y → (2)
Substitute y = 14 + 3x into (1)
6 - 2x = 14 + 3x ( subtract 3x from both sides )
6 - 5x = 14 ( subtract 6 from both sides )
- 5x = 8 ( divide both sides by - 5 )
x = -
Substitute x = - into either of the 2 equations for the corresponding value of y
Substituting into (1)
y = 6 - 2(- ) =
+
=
solution is ( - ,
)
Answer:
Step-by-step explanation:
If the position function is
and we are looking for time when the height is 0, we sub in a 0 for h(t) and solve for t:
and the easiest way to do this is to factor by taking the GCF of -40t:
0 = -40t(t - 5) and by the Zero Product Property,
-40t = 0 or t - 5 = 0. Solving for t, we get
t = 0 (which is before the object is launched) and
t = 5 (which is how long it takes the object to go from the ground, up to its max height, and then back to the ground again).
Your choice is c) 5