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kicyunya [14]
3 years ago
14

Factorise x^3 - 2x^2 -x+2

Mathematics
2 answers:
tankabanditka [31]3 years ago
5 0

Answer:

Solution given:

x^3 - 2x^2 -x+2

take common from two each term

x²(x-2)-1(x-2)

take common again and keep left one on other bracket

<u>(x-2)(x²-1) or (x-1)(x+1)(x-2)</u> is a required answer.

note:using formula a²-b²=(a+b)(a-b) for x²-1.

Dahasolnce [82]3 years ago
5 0

Answer:

(x - 1)(x + 1)(x - 2)

Step-by-step explanation:

x^3 - 2x^2 - x + 2

  • Take x² common from first two terms.

=> x^2(x - 2) -1(x - 2)

  • Take (x - 2) common from whole expression.

=> (x - 2)(x^2 - 1)

  • Factorise (x² - 1) by using the identity → (a² - b²) = (a + b)(a - b)

=> (x - 2)(x + 1)(x - 1)

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What is the sum of the first 37 terms of the arithmetic sequence?
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Answer:

The sum of the first 37 terms of the arithmetic sequence is 2997.

Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is the following:

a_{n+1} = a_{n} + d

In which d is the common diference between each term.

We can expand the general equation to find the nth term from the first, by the following equation:

a_{n} = a_{1} + (n-1)*d

The sum of the first n terms of an arithmetic sequence is given by:

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In this question:

a_{1} = -27, d = -21 - (-27) = -15 - (-21) = ... = 6

We want the sum of the first 37 terms, so we have to find a_{37}

a_{n} = a_{1} + (n-1)*d

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a_{37} = -27 + 36*6

a_{37} = 189

Then

S_{37} = \frac{37(-27 + 189)}{2} = 2997

The sum of the first 37 terms of the arithmetic sequence is 2997.

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