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3 years ago

Find sin(7pie/4) using exact values

Mathematics

1 answer:

rewona [7]3 years ago

3 0

$sin( \frac{ 7\pi }{4} )=-sin(2 \pi - \frac{ 7\pi }{4} )=-sin \frac{ \pi }{4} =- \frac{1}{ \sqrt{2} }$

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Solar panel generates 3/5 of kilowatts of power a warehouse wants to generate 24 kilowatts of power write an expression to find

Anuta_ua [19.1K]

Answer:

The warehouse will need 40 solar panels

Step-by-step explanation:

3/5 kilowatts is generated by 1 solar panel

24 kilowatts will be generated by ?

24 ÷ 3/5 = (24×5)/3 = 120/3 = 40 solar panels.

3 0

3 years ago

Read 2 more answers

HELP ME ASAP!!!!!!!!

Marina CMI [18]

Answer:

Step-by-step explanation:

1) 30 : 100 = x : 299

x = (30 x 299)/100

x = 89,70 $

2) 299 - 89,70 = 209,30 $

3) 5 : 100 = x : 209,30

x = 10,465 $

209,30 + 10,465 = 219,77 $

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3 years ago

katrin2010 [14]

Answer:

A ≈ 35.3 units²

Step-by-step explanation:

Calculate the radius CB using Pythagoras' identity in the right triangle.

CB² + AB² = AC²

CB² + 6² = 9²

CB² + 36 = 81 ( subtract 36 from both sides )

CB² = 45 = r²

Then area of quarter circle is

A = $\frac{1}{4}$ × πr² = $\frac{1}{4}$ × π × 45 ≈ 35.3

6 0

3 years ago

p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.

Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

$\frac{p}{q {r}^{2} } = k$

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

$\frac{200}{2(3) {}^{2} } = k$

$\frac{200}{18} = k$

$\frac{100}{9} = k$

Now, since we know our constant, let find p.

$\frac{p}{q {r}^{2} } = \frac{100}{9}$

Q is 5, and r is 2.

$\frac{p}{5( {2}^{2}) } = \frac{100}{9}$

$\frac{p}{20} = \frac{100}{9}$

$p = \frac{2000}{9}$

3 0

2 years ago

Ami'yan runs every day for exercise at a rate of 1 kilometer every 15 minutes. How many meters does he run in 1 hour? - Thank yo

Alona [7]

Answer:

The total distance covered in 1 hour is 4000 meters.

Step-by-step explanation:

The distance Ami'yan runs is 15 minutes = 1 kilometer

Using the unit formula,

The distance ran in 1 minute = $(\frac{1}{15} ) \textrm{Kilometer}$

Now, 1 hour = 60 minutes

⇒The distance covered in 60 minutes = 60 x (Distance run in 1 minute)

= $60 \times \frac{1}{15} = 4$

So, the distance covered in 1 hour = 4 kilometer

1 kilometer = 1000 meters

⇒ 4 km = 4 x 1000 meters = 4000 m

Hence, the total distance covered in 1 hour = 4000 meters.

6 0

3 years ago