Question

Y= -1/2(x+10)^2+14 Find the range

Answer 1

Answer:

Step-by-step explanation:

y=-1/2(x+10)^2+14

2y=-(x+10)^2+28

(x+10)^2=28-2y

L.H.S.  is  positive.

so 28-2y≥0

28≥2y

or 2y≤28

or y≤ 14

Range is (-∞,14]