A
The velocity is found by differentiating the given cubic.
x'(t) = 2t^3 - 15t^2 + 24t This is the distance
x'(t) = 6t^2 - 20t + 24 This is the velocity (first derivative)
x"(t) = 12t - 20 This is the acceleration (second derivative)
x'(2) = 6(2)^2 - 20*2 + 24
x'(2) = 24 - 40 + 24
x'(2) = 48 - 40
x'(2) = 8 units per second.
x"(2) = 12(2) - 20
x"(2) = 24 - 20
x"(2) = 4 units per second^2
B
at t = 2 the acceleration is positive. That's a pretty good indication that the velocity is increasing.
C
When x(t) is minus, then the particle is moving left.
At t = 0 the object is not moving (x(t) = 0)
Any value less than 0 and the object is moving left. Try a couple of values.
x(-1) = 2(-1)^3 - 15(-1)^2 +24(-1) Whatever that is is minus.
t < 0 will make the object move left.
Scientific notatnio, the first number has to be less than 10
14.35 times 0.1=1.435
we have to make it be able to jump back
1.435 times 10¹ is scientific notaiton
2x + 3y = 1470
3y = -2x + 1470
y = -2/3x + 490 is the equation in slope intercept form.
slope = -2/3
y intercept = 490
allso, can u mark brainlist
Answer:
y≤-x+4
Step-by-step explanation:
x intercept =4
y intercept=4
the shaded area under the solid line because it is greater than or equal
