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aleksandrvk [35]
3 years ago
12

Cody wants to attend the fall festival at school. The price of admission to the festival is $5.50 and each game cost additional

75 cents. If Cody has $15.00 to spend at the festival, whin adch Inequality can be used to solve for g, the number of games that he can play, and what is the maximum number of games he can play?
Mathematics
2 answers:
Lelu [443]3 years ago
5 0

Cody can play a maximum of 13 games.

strojnjashka [21]3 years ago
3 0

Answer:

Cody can play twelve games

Step-by-step explanation:

Remaining amount with Cody after giving the admission price

= 15 - 5.5\\= 9.5\\

If one game costs 75\\ cents then number of games that can be played from 9.5\\ $

= \frac{(9.5*100)}{75} \\= 12\\

Thus , Cody can play twelve games

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Please help!
postnew [5]
Lets solve the equation first:
<span> 0.5 – |x – 12| = –0.25
</span>= 1/2 - |x - 12| = -1/4
= 2 - 4<span>|x - 12| = -1
= 4|x - 12| = 3
= |x - 12| = 0.75
positive case, x >= 12
x - 12 = 0.75
x = 12.75
negative case, x < 12
x - 12 = -0.75
x = 11.25
So those are the two solutions.
These apply:
</span>1.) The equation will have no solutions.
2.) A good first step for solving the equation is to subtract 0.5 from both sides of the equation.
<span>3.) A good first step for solving the equation is to split it into a positive case and a negative case.
</span><span>5.) The negative case of this equation is x – 12 = –0.75.</span>
7 0
4 years ago
Read 2 more answers
You want to put a fence around your large yard. There are two companies that you have found to do the work. They have each given
11111nata11111 [884]

Answer:

200

Step-by-step explanation:

balancing it with 120 is 76 so this what you get

6 0
3 years ago
"Five less than three times a number is greater than two-thirds of that number."
barxatty [35]

Answer:

A.

Step-by-step explanation:

4 0
3 years ago
A businessman was comparing his company's profits for two consecutive months. In November, n, were 0.04 thousand dollars more th
Firdavs [7]
N and d are both numbers of thousands of dollars.
Thus, if n = 1, that means $1000.

Here n = d + 0.4.
Note that in C, n+0.04=n is completely wrong.
Similarly, in D, d = 0.04 = n is completely wrong.
The "combined profit amount" for Nov. and Dec. is n + d = 3.15.

Only A matches this info.  Your answer is A.
5 0
3 years ago
Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x
Serggg [28]

I assume C has counterclockwise orientation when viewed from above.

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

so we first compute the curl:

\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k

\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k

Then parameterize S by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k

where the z-component is obtained from

1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v

with 0\le u\le\dfrac\pi2 and 0\le v\le\dfrac\pi2.

Take the normal vector to S to be

\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k

Then the line integral is equal in value to the surface integral,

\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}

6 0
3 years ago
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