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3 years ago

I need to know the equation for this table!

Mathematics

1 answer:

Kobotan [32]3 years ago

7 0

The equation for the table is y=2x+3.

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3 years ago

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A line connecting a vertex of a scalene triangle with the midpoint of the opposite side is the

Irina18 [472]

The line would be called the median. The definition of 'A line connecting a vertex of a scalene triangle with the midpoint of the opposite side' pertains to the median. There are three medians that connect the scalene triangle.

4 0

3 years ago

Which equation best represents the line that is parallel to 3x -4y=7 and passes through the point (-4,-2)? Select two options.

katovenus [111]

Answer:

The equation that best represents the line that is parallel to 3x - 4y = 7 and passes through the point (-4, -2) is y = 3/4x + 1.

Step-by-step explanation:

3x - 4y = 7 and (-4, -2)

First, solve for y in the equation:

3x - 4y = 7

-4y = -3x + 7

4y = 3x - 7

y = 3/4x - 7/4

m = 3/4 (This will be the slope of the parallel line.) and (-4, -2)

Use the point-slope equation to find the equation that will best represent a parallel line:

y − y1 = m(x − x1)

y - -2 = 3/4(x - -4)

y + 2 = 3/4x + 3 (the 4s cancel out)

(3/4 x 4/1 = 3)

y = 3/4x + 1

The graph that I attached is what these two equations would look like graphed. I am not sure what you mean by two options, I'm sorry!

6 0

3 years ago

What is the simplest form of the expression (14.2a + 9.8b) – (13.1b – 0.2a) – (3.7a + 4.8b)?

Sati [7]

So, the right answer is of option A.

Look at the attached picture⤴

Hope it will help u...

8 0

3 years ago

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Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL

scoray [572]

Answer:

$8(x^2+y^2)-4x-30y+23=0$

Step-by-step explanation:

Distance formula

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let P(x, y) = any point on the locus

Let A = (0, 2)

Let B = (-2, 3)

If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

$PA=\dfrac{1}{3}PB$

Therefore, using the distance formula:

$\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}$

Square both sides:

$\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]$

$\implies x^2+y^2-4y+4=\dfrac{1}{9}(x^2+4x+4+y^2-6y+9)$

Multiply both sides by 9:

$\implies 9x^2+9y^2-36y+36=x^2+4x+4+y^2-6y+9$

$\implies 8x^2+8y^2-4x-30y+23=0$

$\implies 8(x^2+y^2)-4x-30y+23=0$

3 0

2 years ago