Answer:
(-3,-11)
Step-by-step explanation:
Compare the given quadratic equation with the general quadratic equation.
a=1, b=6 and c=-2

Subsitute
for
in given quadratic equation.

The minimum point is (-3,-11).
Answer:
Both air balloon and water balloon data are best modeled by an exponential function.
Step-by-step explanation:
Air balloon
Time (seconds) Volume (cubic centimeters)
0 95
3 69
6 50
9 37
12 27
The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.
(69 - 95)/3 = -8.67
(50 - 69)/3 = -6.33
(37 - 50)/3 = -4.33
(27 - 37)/3 = -3.33
Water balloon
Time (seconds) Volume (cubic centimeters)
0 30
3 15.8
6 7.8
9 4
12 2
(30 - 15.8)/-3 = -4.73
(15.8 - 7.8)/-3 = -2.67
(7.8 - 4)/-3 = -1.27
(4 - 2)/-3 = -0.67
In this case, the relation Volume variation/time also change from point to point.
Then, both air balloon and water balloon data are best modeled by an exponential function.
The direct answer to your question is: "No".
because in that equation, 'x' is not 120 or130.
Let's find out what 'x' actually is:
<u>3/5 x = 52</u>
Multiply each side by 5 : 3x = 260
Divide each side by 3 : <em> x = 86 and 2/3 </em>
T=PV/Rn you just divide both sides by Rn
I hope this helps you
Area=4.pi.r^2
Area =4.3,14.11^2
Area =1519