Answer:
<h2>1. {x | 1 < x < 3}</h2>
Step-by-step explanation:
x + 2 < 5 <em>subtract 2 from both sides</em>
x + 2 - 2 < 5 - 2
x < 3
x - 7 > -6 <em>add 7 to both sides</em>
x > 1
From x < 3 and x > 1 we have 1 < x < 3
Answer:
To solve for n you need to get it by itself
First you want to distribute your 2 through the (3n+14)
-2n+6n+28=-20 (2*3n+2*14= 6n+28)
Now you want to combine any like terms if possible
4n+28=-20 (-2n+6n=4n, both like terms)
Then you want to subtract -28 from both sides
4n=-48 (28-28=0, -20-28=-48)
Lastly you want to divide both sides by 4
n=-12 (4n/4=n, -48/4= -12)
Compute successive differences of the terms.
If they are all the same, the sequence is arithmetic and the common difference is the difference you have found.
If successive pairs of differences have the same ratio, the sequence is geometric and the common ratio is the ratio you have determined.
Example of arithmetic sequence:
1, 3, 5, 7
Successive differences are 3-1 = 2, 5-3 = 2, 7-5 = 2. All the differences are 2, which is the common difference of the sequence.
Example of geometric sequence:
1, -3, 9, -27
Successive differences are -3-1 = -4, 9-(-3) = 12, -27-9 = -36. These are not the same, so the sequence is not arithmetic. Ratios of successive pairs of differences are 12/-4 = -3, -36/12 = -3. These are the same, so the sequence is geometric with common ratio -3.
Answer:
C.
Step-by-step explanation:
15 x 16=240 x 2= 480
57 x 20= 1140
1140 + 480 = 1620
Answer:
22 groups of ten
Step-by-step explanation:
121 plus 116 = 237
237 - 9 = 228
lets split 228 into parts
200
20
8
there are 20 groups of ten in 200
2 groups of ten in 20
and 8 has 0 it is a remainder
20 groups plus 2 groups = 22
22 groups of ten
this probobly isn't the easiest way but I don't know how but this is my thought process.
