Question

Given the equation y = 7 sec(6x– 30) The period is: The horizontal shift is:

Answer 1

Answer:

The period is of $\frac{\pi}{3}$ units.

The horizontal shift is of 30 units to the left.

Step-by-step explanation:

The secant function has the following general format:

$y = A\sec{(Bx + C)}$

A represents the vertical shift.

C represents the horizontal shift. If C is positive, the shift is to the right. If it is negative, it is to the left.

The period is $P = \frac{2\pi}{B}$

In this question:

$y = 7\sec{6x - 30}$

So $B = 6, C = -30$

Then $P = \frac{2\pi}{6} = \frac{\pi}{3}$

The period is of $\frac{\pi}{3}$ units.

The horizontal shift is of 30 units to the left.