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Burka [1]
3 years ago
11

At 2:00 pm there are 350 freshmen and 200 sophomores at a school carnival. After 2:00 pm 20 freshman leave every hour and 35 sop

homores arrive every half hour.
What is the ratio of freshman to sophomores at 4:00 pm in fraction form
Mathematics
2 answers:
deff fn [24]3 years ago
7 0

Answer:

f(4)=350−20(4)200+35(4)=270340=2734.

Step-by-step explanation:

Let x be the number of half-hour intervals since 2:00 p.m.

The number of freshmen can be modeled by P(x)=350−20x and the number of sophomores can be modeled by Q(x)=200+35x.

There are 4 half-minute intervals in two hours, so f(4)=350−20(4)200+35(4)=270340=

27/34.

dmitriy555 [2]3 years ago
5 0

Answer:

160:340

Step-by-step explanation:

The hours between 2:00pm and 4:00pm is 2 hours. If originally 350 freshman and 200 sophomores are at the carnival, and 20 freshman leave every hour, we can determine how many freshman left in 2 hours:

=20\cdot{2}=40

and if 35 sophomores arrive every half our, we know that for every two hours there is 4 half hours, therefore:

=35\cdot{4}=140

The amount of freshman at 4:00pm:

200-40=160

and the amount of sophomores:

200+140=340

the ratio is 160:340

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Someone please help me I’m so confused!!!
QveST [7]

Answer:

number one.  186in^{2}  number two.  36cm^{2}

Step-by-step explanation:

FOR NUMBER ONE:

the area of a trapezoid formula is   \frac{a+b}{2} h where a and b are the bases and h is the height. so we have to add in the numbers into the formula

\frac{12+15}{2} * 6\\ = <em>81</em>

and the paralellogram formula is b×h.  where b is the base and h is height

15 × 7 = <em>105</em>

so the area of the figure is 81 + 105 is 186 in^2

FOR NUMBER TWO:

the area of the square formula is s^{2}.   where s is the side

4^2 = <em>16</em>

and for the paralellogram is b × h

4 × 5 = <em>20</em>

so the area of the figure is 16 +20 = 36 in^2

hope this helps! ;)

5 0
3 years ago
Will mark as brainliest (must show work)
Sever21 [200]

Answer:

46

Step-by-step explanation:

With those problems if you are not given a picture is good we draw one.

Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW  then

m < XVY = m < YVW

      2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms

      2x-x = 15-7, combine like terms

           x = 8

From the picture and the given we see that

m < XVW = m < XVY + m < YVW

m < XVW = 2x+7 + x+15 , combine like terms

m < XVW = 3x + 22, substitute x for 8

m < XVW = 3*8 + 22

m < XVW = 46

Check our work:

m < XVY =  2x+7  = 2*8 +7 = 16 +7 = 23

m < YVW =  x+15 = 8 +15 = 23

m < XVW = m < XVY + m < YVW = 23+23 =46

3 0
2 years ago
Is this a true statement? 0.3711 &gt; 0.3801
disa [49]
NO. It's FALSE.

0.\ 3\ 7\ 1\ 1\\||\ ||\wedge\\0.\ 3\ 8


therefore 0.3801 > 0.3711

4 0
3 years ago
The greatest factor that two or more numbers have in common is the
trapecia [35]

Answer:

 "greatest common factor" (GCF) or "greatest common divisor" (GCD)

Step-by-step explanation:

Apparently, you're looking for the term that has the given definition. It is called the GCF or GCD, the "greatest common factor" or the "greatest common divisor."

_____

The GCF or GCD can be found a couple of ways. One way is to find the prime factors of the numbers involved, then identify the lowest power of each of the unique prime factors that are common to all numbers. The product of those numbers is the GCF.

<u>Example</u>:

  GCF(6, 9)

can be found from the prime factors:

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The unique factors are 2 and 3. Only the factor 3 is common to both numbers, and its lowest power is 1. Thus ...

  GCF(6, 9) = 3¹ = 3

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Another way to find the GCD is to use Euclid's Algorithm. At each step of the algorithm, the largest number modulo the smallest number is found. If that is not zero, the largest number is replaced by the result, and the process repeated. If the result is zero, the smallest number is the GCD.

  GCD(6, 9) = 9 mod 6 = 3 . . . . . (6 mod 3 = 0, so 3 is the GCD)

8 0
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Use the following stem-and-leaf plot to answer the question.<br><br><br>What is the median?
pishuonlain [190]

The median of the stem-and-leaf plot is 23

7 0
3 years ago
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