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maksim [4K]
3 years ago
15

*** Please Help*** Find the 15th term in the pattern 6 ∙ n^2.

Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0
a_{15}=6\cdot15^2=1350
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Please help ASAP!!!! Which numbers are perfect squares? Check all that apply. A.20 B.40 C.64 D.4 E.49 F.48
natali 33 [55]

Answer: 20 is not

40 is not

64 is

4 is

49 is

48 is not

Step-by-step explanation:

6 0
3 years ago
-4.3&lt;-2.91&lt;5.7 <br>is that that true?
IRISSAK [1]
Yes that is correct
7 0
3 years ago
The two congruent angles in an isosceles triangle measure 3X + 10o and 5X - 16o . What value of X makes this relationship true?
aliya0001 [1]
So for this you need to set them equal to each other! 3x+100=5x-160
now you combine like terms and solve!
8 0
3 years ago
Whats the equation of a circle centered at (7,1) that passes through (-2,10)
castortr0y [4]
The line from (7, 1) to (-2 10) is a radius of the circle.

Its length is the square root of [ (-2 - 7)² + (10 - 1)² ] =  √(81 + 81) = √162

The equation of the circle is: (x- 7)² + (y - 1)² = 162 
6 0
3 years ago
Consider the formula for the average velocity, v, of a moving particle. In the formula, d, and dy represent the distance travele
il63 [147K]

Answer:

Option C.

Step-by-step explanation:

Note: The question and options are  not in correct form.

Let the correct question is "Consider the formula for the average velocity, v, of a moving particle. In the formula, d1 and d2 represent the distance traveled by the particle at times t1 and t2 respectively.

v = (d2 - d1)/(t2 - t1)  

Which of the following equations is equivalent to the formula for velocity?

A. t1=v(d2-d1)-t2

B. d1=v (t2-t1)-d2

C. d2=v(t2-t1)+d1

D. t2=v(d2-d1)+t1 "

The given formula is  

v=\dfrac{d_2-d_1}{t_2-t_1}

On cross multiplication, we get

v(t_2-t_1)=d_2-d_1

Add d_1 on both sides.

v(t_2-t_1)+d_1=d_2-d_1+d_1

v(t_2-t_1)+d_1=d_2

Since, d_2=v(t_2-t_1)+d_1, therefore, the correct option is C.

5 0
3 years ago
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