*** Please Help*** Find the 15th term in the pattern 6 ∙ n^2.

What is the value of n in the equation below? 12^n/12^5=12^4

Flura [38]

12^n
------- = 12^4
12^5

Let's clear out the fraction. To do this, mult. both sides by 12^5:

12^n = (12^4)(12^5) = 12^9 Then n = 9 (answer)

8 0

4 years ago

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The data below are the frequency of cremation burials found in 17 archaeological sites. a. Obtain the mean, median, and mode of

Sergeeva-Olga [200]

Answer:

(a) The mean of the data is 275.

(b) The median of the data is 85.

(c) The mode of the data is 45.

(d) The measure of center that works best here will be median.

Step-by-step explanation:

We are given below the frequency of cremation burials found in 17 archaeological sites. Arranging those in ascending order we get;

28, 31, 32, 45, 45, 47, 59, 67, 85, 86, 143, 256, 272, 390, 424, 524, 2141.

(a) The formula for calculating mean for the above data is given by;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{28+ 31+ 32+ 45+ 45+ 47+ 59+ 67+ 85+ 86+ 143+ 256+ 272+ 390+ 424+ 524+ 2141}{17}$

= $\frac{4675}{17}$ = 275

So, the mean of the data is 275.

(b) Since, the number of observations (n) in our data is odd (i.e. n = 17) , so the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

= $(\frac{17+1}{2} )^{th} \text{ obs.}$

= $(\frac{18}{2} )^{th} \text{ obs.}$

= $9^{th} \text{ obs.}$ = 85

So, the median of the data is 85.

(c) Mode is that value in our data which appears maximum number of times in our data.

So, after observing our data we can see that only number 45 is appearing maximum number of times (2 times) and all other numbers are appearing only once.

So, the mode of the data is 45.

(d) The measure of center that works best here will be median because there are outliers in our data (means extreme values) and mean gets affected by the outliers.

So, the best measure would be median as it represents the middle most value of our data.

4 0

3 years ago

How many ways are there to select 7 countries in the United Nations to serve on a council if 3 is selected from a block of 54, 1

Strike441 [17]

Answer:

Total number of ways will be $=8.44727\times 10^{10}ways$

Step-by-step explanation:

We have to select 7 countries

3 countries selected from a block of 54

So number of ways of selecting these three countries $=^{54}c_3=\frac{54!}{3!51!}=\frac{54\times 53\times \times 52\times 51!}{6\times 51!}=24804ways$

Now 1 country is selected from 66 block

So number of ways to select 1 country = $=^{66}c_1=\frac{66!}{1!65!}=\frac{66\times \times 65!}{1\times 65!}=65ways$

Now next 3 country is selected from 69 country

So $=^{69}c_3=\frac{69!}{3!66!}=\frac{69\times68\times 67 \times 66!}{6\times 66!}=52394ways$

So total number of ways to select 7 countries = 24804×65×52394 $=8.44727\times 10^{10}ways$

8 0

3 years ago

I need help if you can help me thank you.....

kumpel [21]

Team a scored more point than team b.

5 0

3 years ago

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Jane travels7 mph less than2 times as fast as Mike. Starting at the same point and traveling in the same direction, they are198

Sphinxa [80]

Let:

Vj = Speed of jane

Vm = Speed of mike

d = distance

t = time

Jane travels 7 mph less than 2 times as fast as Mike, therefore:

Vj = 2Vm - 7

Remeber:

distance = speed*time

Distance traveled by mike:

d=Vm*t = Vm*6

Distance traveled by jane:

d + 198 = Vj*6

where:

Vj = 2Vm - 7

d + 198 = (2Vm-7)*6

Now, let:

d=Vm*6 (1)

d + 198 = (2Vm-7)*6 (2)

Replace (1) into (2)

6Vm + 198 = 12Vm - 42

Subtract 6Vm from both sides:

6Vm + 198 - 6Vm = 12Vm - 42 - 6Vm

198 = 6Vm - 42

Add 42 to both sides:

198 + 42 = 6Vm - 42 + 42

240 = 6Vm

Divide both sides by 6:

240/6 = 6Vm/6

40 = Vm

Vm = 40mph

Replace Vm into this equation Vj = 2Vm - 7 :

Vj = 2(40) - 7 = 80 - 7 = 73mph

4 0

1 year ago