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3 years ago

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Erik pays 225 in advance on his account at the athletic club. Each time he uses the club , $9 is deducted from the account , wri

te an equation that represents the value remaining in his account after x visits to the club . Find the value remaining after 7 visits

1 answer:

zhenek [66]3 years ago

3 0

Answer:

225÷ 9?

Step-by-step explanation:

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Rina wants to ride the bumper cars 1 time and the Ferris wheel 5 times. It costs 1 ticket to ride the bumper cars and 1 ticket t

Lana71 [14]

Answer:

Rina will need 6 tickets.

Explanation:

Rina needs only 1 ticket to ride the ferris wheel once, and 1 ticket to ride the bumper cars once. If she wants to ride the ferris wheel 5 times, then she'll need 5 tickets since 1 x 5 = 5. If she wants to ride the bumper cars only once, she'll only need 1 ticket since 1 x 1 = 1.

Add the answers together, and you get 6 tickets since 5 + 1 = 6.

Hope this helps! :)

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4 years ago

Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

6 0

3 years ago

How would you solve <br> y - 4 = 3

slega [8]

Answer:

Y = 7

Step-by-step explanation:

You would add 4 to both sides to cancel out the -4. That leaves y by itself equaling 7.

3 0

3 years ago

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user100 [1]

Answer:

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14√x+15 = 71

14√x+15-15 = 71-15 = 56

14√x/14 = 56/14 = 4

√x^2 = 4^2 = 16

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3 years ago

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V = lwh
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4 years ago