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4 years ago

How do you know whether two quantities x and y are proportional?

Mathematics

1 answer:

Yuri [45]4 years ago

4 0

Answer: a. Every ratio yx for related pairs of x and y is equivalent.

Step-by-step explanation: The proportionality between two variables x and y is established using the proportionality relation.

x = ky where k is a constant and k = x / y. Hence every ratio of both numbers for a rated pair are equivalent once x and y ≠ 0

You might be interested in

Find the student’s error in solving the following inequality. 31 < –5x + 6 25 < –5x –5 < x

zaharov [31]

Answer:

He subtracted -5 from both sides, not -6

Step-by-step explanation:

The inequality that we have to solve in this problem is

$31$

To solve the inequality, we proceed as follows:

First, we isolate the term in x. To do that, we add -6 on both sides of the inequality, and we find:

$31-6$

So, this is now the new inequality.

Then, we divide both sides of the equation by 5; we get:

$\frac{25}{5}$

Finally, we change sign to the inequality, so we get:

$x$

So, the student's error is that he subtracted -5 from both sides, not -6.

7 0

3 years ago

maddy wants to rent a faster scooter. it costs 10.00, plus 4.25/h she has 27.00 how many hours can maddy rent the faster scooter

Gemiola [76]

Since the scooter costs $10, we can subtract $10 from $27.
That leaves us with $17.
The scooter costs $4.25/hr, so:
17/ 4.25 = the hours that Maddy can rent the scooter for.
17/ 4.25 = 4
Maddy can rent the scooter for 4 hours.

4 0

3 years ago

. The first day of a water polo tournament the total value of tickets sold was $17,610. One-day passes sold for $20 and tourname

Scilla [17]

Answer:

330 day passes, 367 tournament passes

Step-by-step explanation:

5 0

3 years ago

If ax-7=b(x+2) then x =

Maslowich

Move all terms to the left side and set equal to zero. Then set each factor to equal to zero giving you..

8 0

3 years ago

Use the quadratic formula to find both solutions to the quadratic equation<br> given below.

Tpy6a [65]

The solution of the equation are $x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

<h3>How to determine the solution?</h3>

The equation is given as:

3x^2 - 7x- 1 = 0

The quadratic equation is represented as:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

So, we have:

$x = \frac{7 \pm \sqrt{(-7)^2 - 4 *3 *-1}}{2*3}$

Evaluate the expression

$x = \frac{7 \pm \sqrt{61}}{6}$

Expand

$x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

Hence, the solution of the equation are $x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

Read more about quadratic formula at:

brainly.com/question/1214333

#SPJ1

5 0

2 years ago