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2 years ago

10

A survey indicates that there are approximately 120 dairy farms in a given area. If there are exactly 400 farms, and exactly 20%

of them are dairy farms, what is the percent error? Fill in the table below.

2 answers:

kaheart [24]2 years ago

6 0

Answer:

a = 120

b = 80

c = 40

d = 0.5

e = 50%

Step-by-step explanation:

inna [77]2 years ago

5 0

Answer:

120 out of 400 does not equal 20%

it equals 30%

Step-by-step explanation:

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Please help me! I need it

Studentka2010 [4]

Answer:

About 0.5

Step-by-step explanation:

By the law of sines:

$\dfrac{2}{\sin 105}=\dfrac{c}{\sin 15} \\\\\\c=\dfrac{2}{\sin 105}\cdot \sin 15\approx 0.5cm$

Hope this helps!

3 0

2 years ago

Using the image, determine the length of each arc.<br> m RC=<br> m CBR =

Montano1993 [528]

<u>Given</u>:

Given that the measure of ∠CDR = 85°

We need to determine the measure of $\widehat{RC}$ and $\widehat{CBR}$

<u>Measure of arc RC:</u>

Since, we know that if a central angle is formed by two radii of the circle then the central angle is equal to the intercepted arc.

Thus, we have;

$m\angle CDR = m \widehat{RC}$

Substituting the values, we get;

$85^{\circ} = m \widehat{RC}$

Thus, the measure of $\widehat{RC}$ is 85°

<u>Measure of arc CBR:</u>

We know that 360° forms a full circle and to determine the measure of arc CBR, let us subtract the values 360 and 85.

Thus, we have;

$m\widehat{CBR}=360^{\circ}-m \widehat{RC}$

Substituting the values, we have;

$m\widehat{CBR}=360^{\circ}-85^{\circ}$

$m\widehat{CBR}=275^{\circ}$

Thus, the measure of $\widehat{CBR}$ is 275°

6 0

2 years ago

Explain this picture

geniusboy [140]

My spine :)))))))))))))

3 0

1 year ago

The average daily high temperature in Seattle is modeled by the function T = –15 cos(πm/6)+ 61, where T is the temperature in °F

Sliva [168]

Answer:

$m = 6$

Step-by-step explanation:

$T = -15cos(\frac{\pi m}{6}) +61$

$76 = -15cos(\frac{\pi m}{6}) +61$

$76-61 = -15cos(\frac{\pi m}{6})$

$15 = -15cos(\frac{\pi m}{6})$

$\frac{15}{-15} = cos(\frac{\pi m}{6})$

$-1 = cos(\frac{\pi m}{6})$

$cos^{-1}( -1) = \frac{\pi m}{6}$

$\pi = \frac{\pi m}{6}$

$6\pi = \pi m$

$m = 6$

7 0

1 year ago

Please help me with precal

Doss [256]

Consider the function $f(x)=\sqrt{x}.$ This function has:

the domain $x\in [0,\infty);$
the range $y\in [0,\infty).$

If the domain of unknown function is $[a,\infty),$ then $x\ge a$ or $x-a\ge 0.$ This means that you have $\sqrt{x-a}$ as a part of needed function.

If the range of unknown function is $[b,\infty),$ then $y\ge b.$ This means that you have to translate function b units up and then the expression of the function is

$y=\sqrt{x-a}+b.$

Answer: correct choice is B.

6 0

2 years ago