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3 years ago

Graph the linear equation. Find three

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

8 0

Answer:

3,4

6,6

9,8

Step-by-step explanation:

Karo-lina-s [1.5K]3 years ago

4 0

-3y = -2x -6

Y= 2/3x + 2

When x= 3
Y= 2/3(3) + 2
Y= 2+2 = 4

(3,4)

When x= 6
Y=2/3(6)+2
Y= 4+2 = 6

(6,6)

When x= 12
Y= 2/3(12) + 2
Y= 8+2=10

(12,10)

You might be interested in

What's the sum of two integers with different signs is 8

dem82 [27]

16 + (-8) = 8 <== here is one
16 - 8 = 8
8 = 8 (correct)

-12 + 20 = 8 <== and another
11 + (- 3) = 8 <== and another

7 0

3 years ago

HELP PLEASE i dont understand at all...

bija089 [108]

An exponent signifies repeated multiplication.

$x\cdot x\cdot x=x^{3}$ the factor x is repeated 3 times

Exponents can be added and subtracted to express the effects of multiplication and division.

$\dfrac{x\cdot x\cdot x\cdot x\cdot x}{x\cdot x\cdot x}=\dfrac{x^{5}}{x^{3}}\\\\=\dfrac{x\cdot x\cdot x}{x\cdot x\cdot x}\cdot x\cdot x=x\cdot x\\\\=x^{(5-3)}=x^{2}$

The addition and subtraction of exponents works the same even when there are more denominator factors than numerator factors.

$\dfrac{x\cdot x\cdot x}{x\cdot x\cdot x\cdot x\cdot x}=\dfrac{x^{3}}{x^{5}}=\dfrac{1}{x^{2}}\\\\=x^{(3-5)}=x^{-2}$

That is, a negative numerator exponent is the same as a positive denominator exponent and vice versa. You can move a factor with an exponent from denominator to numerator and change the sign of the exponent, and vice versa.

Your expression has 3 in the denominator with a negative exponent. It can be moved to the numerator and the exponent changed to positive:

$\dfrac{1}{3^{-2}}=3^{2}\\\\=3\cdot 3=\bf{9}$

8 0

3 years ago

I need the answer asap

eimsori [14]

Answer:

22873

Step-by-step explanation:

you have to put the value from 6-94 in n the given equation 5n+7.

for e.g= (5×6+7)+(5×7+7)+(5×8+7)+ _____ so on

3 0

3 years ago

What is the equation of the quadratic graph with a focus of (3, 6) and a directrix of y = 4? f(x) = one fourth (x − 3)2 + 1 f(x)

mina [271]

Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|

Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5

Required answer is f(x) = one fourth (x - 3)^2 + 5

8 0

3 years ago

Please help! It would be very much appreciated :)

Trava [24]

Answer:

Cos 45=6/x

x=6/cos 45=6√2

x=6√2

tan 45=y/6

y=tan45 ×6

y=6

sin 60=y/10

y=sin60×10

y=5√3

again

Cos 60=x/10

x=½×10

x=5

Sin 45=x/5

x=1/√2×5 or

x=5√2/2

again

y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]

Sin 30=8/x

½×x=8

x=8*2

x=16

again

cos 30= y/x

√3/2×16=y

y=8√3

sin 60=7/x

x=7/[√3/2]

x=14/√3 or 14√3/3

again

cos 60=y/x

½×14√3/3=y

7√3/2=y

y=7√3/2

Note:

Sin angle =perpendicular/hypotenuse

Cos angle =base/hypotenuse

Tan angle =perpendicular /base

7 0

3 years ago