What are the radian measures of all angle whose sine is?

Mathematics

1 answer:

ehidna [41]2 years ago

6 0

I believe if i am getting your context right, the answer is 0.64

You might be interested in

Select the correct answer.<br> What are the solutions of this quadratic equation?<br> 25x^2 + 1 = 0

Llana [10]

Answer:

no solution because the square root of a negative number is not a real number d=-100

4 0

2 years ago

One night Puvi spent 1/3 of his money on dinner and then 1/4 of the remaining money on dessert. He then had just enough left so

arsen [322]

Answer:

Step-by-step explanation:

Cost of two tickets = 2 * 30 = £60

Let the amount with Puvi = £x

Money spent on dinner = (1/3)*x

$= \dfrac{1}{3}x$

$Remaining \ money =x - \dfrac{1}{3}x =\dfrac{3}{3}x-\dfrac{1}{3}x=\dfrac{2}{3}x$

$Money \ spent \ on \ dessert = \dfrac{1}{4} *\dfrac{2}{3}x =\dfrac{1}{6}x\\\\\\$

Total money - money spent on dinner - money spent on dessert = 60

$x -\dfrac{1}{3}x -\dfrac{1}{6}x=60\\\\\\\dfrac{6}{6}x-\dfrac{1*2}{3*2}-\dfrac{1}{6}x =60\\\\\\\dfrac{6}{6}x-\dfrac{2}{6}x-\dfrac{1}{6}x=60\\\\\\\dfrac{6-2-1}{12}x=60\\\\\\\dfrac{3}{12}x=60\\\\\\x=60*\dfrac{12}{3}=60*4=240$

Money that Puvi had at the start of the night = £ 240

8 0

2 years ago

Can someone help me on this

Vladimir79 [104]

Answer:

Step-by-step explanation:

8 0

3 years ago

Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .