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Lunna [17]
3 years ago
13

Simplify. Please select the best answer from the choices provided

Mathematics
2 answers:
ehidna [41]3 years ago
6 0

The answer is 3 because 1/3 of 3 is 1 and 1/3 of 9 is 3 and 3 times 1 is 3

Answer: 3

Snezhnost [94]3 years ago
4 0

3^{\frac{1}{3}} \times 9^{\frac{1}{3}} =

= 3^{\frac{1}{3}} \times (3^2)^{\frac{1}{3}}

= 3^{\frac{1}{3}} \times 3^{\frac{2}{3}}

= 3^{\frac{1}{3} + \frac{2}{3}}

= 3^1

= 3

Answer: C. 3

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Answer:

To the nearest hundred dollars, the car will be worth $17,900 by 2005

Step-by-step explanation:

Firstly, we need to write the depreciation equation

We have this as:

V = I(1 - r)^t

V is the present value which is what we want to calculate

I is the initial value, the amount the cad was bought which is $22,000

r is the rate of change which is 5% = 5/100 = 0.05

t is the time difference which is 2005-2001 = 4

Substituting all these into the depreciation equation, we have it that

V = 22,000(1 -0.05)^4

V = $17,919.1375

To the nearest hundred dollars, that would be;

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