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Norma-Jean [14]

3 years ago

5

a tennis racket normally costs $80. the tennis racket is on sale for 40% off. what is the sale price of the tennis racket.

2 answers:

lbvjy [14]3 years ago

8 0

Answer:$48.00

Step-by-step explanation:(80 x 40)/100 = $32.00

80 - 32.00 = $48.00

Olegator [25]3 years ago

7 0

Answer:

$48

Step-by-step explanation:

80 multiplied by 0.40 is 32. So 80-32=48

Hope this helps!

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Jake went on a riverboat tour. After returning from the tour, he was curious to know the speed at which the boat was going. Duri

atroni [7]

I'm sorry I'm too lazy to read all of that. However, I did get the main point. The river was going at 3 mph. Since he wanted to travel 10 miles upstream and downstream, you would have to subtract 20 by 3. This would mean he was going at a speed of 17 mph.

4 0

3 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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cupoosta [38]

Hope this helps you with your questions.

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2 years ago

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Stels [109]

3*2 probably I’m sorry if it’s wrong

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Sonbull [250]

Answer:

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Step-by-step explanation:

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2 years ago

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