2y^3 – 2y – 10y + 10 + y^2 – 1 < 0 [the terms are simply reorganized again]
factor 2y from the first two terms, -10 from the second two terms
2y (y^2 -1) – 10 (y-1) + y^2 – 1 < 0
2y (y+1)(y–1) – 10 (y-1) + (y+1)(y–1) < 0 [ because y^2 – 1 = (y+1)(y–1) ]
factor out (y-1) from all the terms
(y-1) [2y(y+1)-10+ y+1] < 0
(y-1) [(y+1) (2y+1) - 10] < 0
Let us simplify (y+1) (2y+1) - 10 < 0 now
(y-1) (2y^2+y+2y+1-10) < 0
(y-1) (2y^2 +3y -9 < 0
(y-1) (2y^2 +6y -3y - 9) < 0 [ because 3y = 6y -3y] j
Answer:
slope = - 
Step-by-step explanation:
Calculate the slope m using the slope formula
m = 
with (x₁, y₁ ) = (- 3, - 4) and (x₂, y₂ ) = (- 6, - 2)
m = 
= 
= -
Hi there , solution is in the figure attached with...hope it helps u
Answer:
Heyyyy!!
The answer is 66.9
please read the explanation... it will help... I promise
Step-by-step explanation:
Okay... Here we go...
The context mentions that the two quadrilaterals are similar... meaning their sides are proportional...
So... you basically have to find the scale factor...
(the math itself is easier than the explanation...
51/16 = 3.1875 (that is the number we multiplied the sides of quadrilateral FGHI to get quadrilateral JKLM...
so to get side JK all you have to do is multiply that scale factor by side FG... which after the use of a calculator results in 66.9 (i rounded, and used a calculator... lol)
but yeah... i hope this helps...
If the distance is equal to the counted number of seconds divided by 3, then multiply the distance by 3 to determine the number of counted seconds . . (5 km)(3) = 15 seconds counted between lightning and thunder.
