12 divided by 0.3 equals 40
9514 1404 393
Answer:
250
Step-by-step explanation:
Let 'a' represent the number of adult tickets.
a +(a -73) = 427
2a = 500 . . . . . add 73
a = 250 . . . . . . divide by 2
250 adult tickets were sold.
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<em>Additional comment</em>
I call this a "sum and difference problem" because we are given the total of two values and the difference between them. As you can see here, the larger of the two values is the average of the given numbers, their sum divided by 2. This is the generic solution to such a problem: the larger number is the average of the given sum and difference.
Step-by-step explanation:
To find the solution, Tanisha can graph each side of the equation as its own function:
y₁ = log₃(5x)
y₂ = log₅(2x + 8)
The solution is where the two curves cross. From the graph, that happens at x ≈ 0.957.
desmos.com/calculator/lkukjhn3g2
So first you want to find how much the second car gains on the first car in one hour.
Since the second car travels 65 kph, but the first travels 40, we can just subtract 40 from 65 to find how much faster the second car is than the first.
65 - 40 = 25
So the second car is 25 kph faster than the first.
Since the first car had a 2 hour head start, we first want to calculate how far away the first car got from the sign before the second car reached the sign.
So just 2 hours * 40 kph, which gives you 80 kilometers.
So now we know the second car has to gain 80 km on the first car in order to overtake it.
Since the second car gains 25 km per hour on the first car, we can just divide 80 by 25.
80 / 25 = 16/5, or in decimal form 3.2.
So the second car will overtake the first car in 3.2 hours, or 192 minutes, which is also 3 hours and 12 minutes.
It depends on how long the wedding is. Marvin has a $15 lower flat fee but a $4.50 more expensive hourly fee. Therefore, if the wedding is longer than 15/4.50=3.33 hours, it would make more sense to go with Dave. If the wedding is shorter than 3.33 hours, it makes more sense to go with Marvin.
