All categories

2 years ago

All numbers streets runs parallel to each other both 3rd and 4 the streets are intersected by king Ave

Mathematics

1 answer:

erastova [34]2 years ago

5 0

Answer:

Step-by-step explanation:

King avenue becomes the base

He turns left into the side meet right angle side.

Therefore the hypotenuse cuts through the houses and becomes a measure

Hypotenuse + King Ave B = 3rd Street A

Hypotenuse + 7000mB = 3rd St 5000m A.

H^2= 7m^2B - 5m^2A

√H74 = √25A +√B49

H = √H74 = 8600m

You might be interested in

Please help and give a explanation I will give brainliest and 25 points

Doss [256]

Answer:

Addition: -1 + -3 = -4

Subtraction: (-4) - 5 = -10

Step-by-step explanation:

Since adding a positive makes a negative number stay negative, it equals -4.

Then by subtracting a negative with a positive (5), the number stays negative once again, which then equals -10.

8 0

2 years ago

Can someone help me with 9,10,11 ?

sergij07 [2.7K]

I could be wrong but i graphed it out and 9 is C , 10 is A , and 11 is C Hopefully it's right

3 0

2 years ago

Find the number of bit strings that satisfies the given conditions. The bit strings of length 11 having at least four 1s

Rainbow [258]

Answer:

Step-by-step explanation:

3 0

2 years ago

Find the matching statement?

Nesterboy [21]

1. F
2. C
3. B
4. A
5. D
6. E

8 0

2 years ago

Find the tangent of ∠I.

Nady [450]

Answer:

tanI = $\frac{\sqrt{70} }{5}$

Step-by-step explanation:

We require to calculate GH using Pythagoras' identity in the right triangle.

GH² + GI² = HI²

GH² + 5² = ( $\sqrt{95}$ )²

GH² + 25 = 95 ( subtract 25 from both sides )

GH² = 70 ( take square root of both sides )

GH = $\sqrt{70}$

Then

tanI = $\frac{opposite}{adjacent}$ = $\frac{GH}{GI}$ = $\frac{\sqrt{70} }{5}$

4 0

2 years ago