Answer:
<em>The registers that are compared are instructions 3 and 4</em>
<em>Explanation:</em>
<em>From the question given,</em>
<em>Recall that we need to explain what the hazard detection unit is doing during the 5th cycle of execution and which registers are being compared.</em>
<em>Now,</em>
<em>The instructions on the 5th cycle, at the stage ID/EX and IF/ID:</em>
<em>The instruction values are in ID/EX : sub $t2, $t3, $t6 (instruction 3)</em>
<em>The instruction values are in IF/ID: sub $t3, $t1 $t5 (instruction 4)</em>
<em>The register $t3 is compared in the instructions 3 and 4</em>
<em>The hazard detection unit between instruction 4 and 5t o be compared, it need to find out the values of $t1</em>
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A device that sucks bc mien broke
It is also called running it. Hope this helps!!!
Answer:
The correct option is;
Selecting the correct browser to use for the sites you want to visit
Explanation:
Censorship of information is the subduing of information based on the consideration of such information being harmful or inconvenient
Increased anonymity
Making an individual anonymous which is one of the capabilities of the internet, is seen as encouraging unethical behavior and promoting discussions which are deemed uncivil in a commonly shared space online.
Unauthorized sharing of copyrighted information
The sharing and distribution of copyrighted material is against the law but it is a common occurrence and in various formats online
Out of the given options, selecting the correct browser to use for the sites you want to visit is the one that is not a concern.
Answer:
Written in C++
void number(int n){
if(n%2 == 0)
cout<<2 * n;
else
cout<<5 * n;
}
Explanation:
The programming language is not stated.
However, I answered using C++
This line defines the function as void
void number(int n){
This line checks if the number is even
if(n%2 == 0)
If yes, it doubles the number and prints the output
cout<<2 * n;
If otherwise,
else
It multiplies the number by 5 and prints the output
cout<<5 * n;
}
To call the function from main, use:
number(n);
Note than n must be declared as integer
See attachment
