Given two positive even integers, it turns out that the square of the largest minus 10 times the smaller is 76. What is the sum
of the integers?
Please help....
Please help....
1 answer:
Answer:
26
Step-by-step explanation:
Even integers will only have a square ending in 6 if they end in 4 or 6.
The square will only have a value greater than 76 if the number is greater than 8, that is, 14 or 16, 24 or 26, and so on.
The "smaller" integer will only be smaller if the "larger" integer is less than 16.
So, the two integers are ...
14 and (14^2 -76)/10 = 12
The sum of 14 and 12 is 26.
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In the graph, we let x represent the "larger" integer and y the "smaller". The shaded area is where x > y, and the curve is the constraint on their values. The two vertical lines are the even numbers whose squares end in 6, resulting in integer values for y.
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Answer:
4 ft.
Step-by-step explanation:
We can consider the orignial square's sides to be x, so area of the original figure:
The new rectangle's sides will be x and x+8, so the area of the new figure will be x^2+8x.
We know that the new area is 3 times the old one. So our equation will be:
x^2+8x=3x^2
our answer will be x=4.
Therfore, the length of the side of the old flower bed is 4 ft.