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love history [14]
3 years ago
14

Given two positive even integers, it turns out that the square of the largest minus 10 times the smaller is 76. What is the sum

of the integers?
Please help....

Mathematics
1 answer:
kolbaska11 [484]3 years ago
3 0

Answer:

  26

Step-by-step explanation:

Even integers will only have a square ending in 6 if they end in 4 or 6.

The square will only have a value greater than 76 if the number is greater than 8, that is, 14 or 16, 24 or 26, and so on.

The "smaller" integer will only be smaller if the "larger" integer is less than 16.

So, the two integers are ...

  14 and (14^2 -76)/10 = 12

The sum of 14 and 12 is 26.

_____

In the graph, we let x represent the "larger" integer and y the "smaller". The shaded area is where x > y, and the curve is the constraint on their values. The two vertical lines are the even numbers whose squares end in 6, resulting in integer values for y.

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John has gross biweekly earnings of $743.61. By claiming 1 more withholding allowance, John would have $19 more in his take home
Afina-wow [57]

Answer:

Total withholding allowances are 39.

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3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 402 gram setting. It is
lidiya [134]

Answer:

The value of t test statistics is -2.25.

Step-by-step explanation:

We are given that a manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 402 gram setting. It is believed that the machine is under filling the bags.

A 25 bag sample had a mean of 393 grams with a standard deviation of 20.

<u><em>Let </em></u>\mu<u><em> = mean filling of bags by the machine.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 402 gram     {means that the the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 402 gram     {means that the the machine is under filling the bags}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean bag filling = 393 grams

            s = sample standard deviation = 20 grams

            n = sample of bags = 25

So, <u><em>test statistics</em></u>  =  \frac{393-402}{\frac{20}{\sqrt{25} } }  ~ t_2_4

                               =  -2.25

The value of t test statistics is -2.25.

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