1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
love history [14]
3 years ago
14

Given two positive even integers, it turns out that the square of the largest minus 10 times the smaller is 76. What is the sum

of the integers?
Please help....

Mathematics
1 answer:
kolbaska11 [484]3 years ago
3 0

Answer:

  26

Step-by-step explanation:

Even integers will only have a square ending in 6 if they end in 4 or 6.

The square will only have a value greater than 76 if the number is greater than 8, that is, 14 or 16, 24 or 26, and so on.

The "smaller" integer will only be smaller if the "larger" integer is less than 16.

So, the two integers are ...

  14 and (14^2 -76)/10 = 12

The sum of 14 and 12 is 26.

_____

In the graph, we let x represent the "larger" integer and y the "smaller". The shaded area is where x > y, and the curve is the constraint on their values. The two vertical lines are the even numbers whose squares end in 6, resulting in integer values for y.

You might be interested in
What is 500 divided by 6.7
pishuonlain [190]
\boxed{ \frac{500}{6.7} = 74.627\ Answer}
7 0
3 years ago
The sum of two numbers is 74. One number is 6 times less than 4 times the second number. Find the two numbers.
OLEGan [10]
I'll get you started. Let x and y be the two numbers. we have:                      x  +  y  =  74      (sum is 74)                       x  =  4y  - 6        (the number x is six less than 4 times y) Now that you have the equations use an algebraic techniques to eliminate one variable thereby solving for the other. If you need more help add a comment to your question.


3 0
3 years ago
Orthogonal explanatory variables. suppose in the modelx2 to xk are all uncorrelated. such variables are called orthogonal variab
sertanlavr [38]
<span>d. suppose you have run the regression and afterward you want to introduce another orthogonal variable, say, xk 1 into the model. do you have to recompute all the previous coefficients 1 to k? why or why not?</span>
4 0
3 years ago
Granted DVD ever DVD and bc bc rn even if sm can ms rn get th bee lol you can go to
tester [92]
WhAt dO YoU MeAn???
Huh??
6 0
2 years ago
If shown, AB and CD are straight lines. Find x in each case.
nlexa [21]

Answer:

x = 60

Step-by-step explanation:

Vertical opposite angles are formed when two straight lines intersect each other.

Given that AD and CD are two straight lines intersecting at O, the two vertical opposite formed are, ∠AOD and ∠COB. Therefore:

∠AOD = ∠COB (Vertical opposite angles are congruent)

∠AOE = 90° (right angle)

∠DOE = x

∠COF = 30°

∠BOF = 2x

m∠AOE + m∠DOE = m∠AOD (angle addition postulate)

90 + x = ∠AOD (Substitution)

m∠COF + m∠BOF = m∠COB (Angle addition postulate)

30 + 2x = ∠COB

m∠AOD = m∠COB (vertical opposite angles)

90 + x = 30 + 2x (Substitution)

Collect like terms

90 - 30 = 2x - x

60 = x

x = 60

4 0
3 years ago
Other questions:
  • 1.)Each sandwich costs $.02 per cubic inch to make. What is the cost of each sandwich?
    14·1 answer
  • Which toy pack has a cost of $2.50 per toy?
    15·2 answers
  • The commutative property only works under what two operations?
    13·1 answer
  • Graph the linear equation -4y=-5x-18​
    11·1 answer
  • Which expression is equivalent to 15a^8b^4/5a^4b?<br> 3a^2b^4<br> 3a^4b^3<br> 10a^4b^3<br> 10a^4b^4
    6·1 answer
  • You start school at 9:00 am, your doing work, an hour and 7 minutes has passed, what time is it now? What time does the meeting
    15·1 answer
  • HELP ASAP!!!20pts<br><br> 1/3x=−20<br><br> WHAT IS X?
    7·2 answers
  • PLS ANSWER!!!!<br> which of the following equations corresponds to the table below?
    7·1 answer
  • Please help!!!!!!!!!!!!!!!!!!!!!!
    7·2 answers
  • Solve the unknown<br>21​
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!