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3 years ago

When a force causes an object to move, what happens?

Mathematics

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

The object moves in the direct the <u>net force</u> is applied.

Step-by-step explanation:

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Find 85% of the number 33.51 help

Makovka662 [10]

33.51 X 85% (0.85) = 28.48

5 0

2 years ago

Read 2 more answers

The opposite sides of a parallelogram have measures (2x+10) cin and (x+15)

xz_007 [3.2K]

Answer:

The measure of the sides is 20 cm.

Step-by-step explanation:

Opposite side of a parallelogram:

Opposite sides of a parallelogram are congruent, that is, they have the same measure.

Measures (2x+10) cm and (x+15) cm:

This means that:

$2x + 10 = x + 15$

$2x - x = 15 - 10$

$x = 5$

2x + 10 = 2*5 + 10 = 10 + 10 = 20

The measure of the sides is 20 cm.

6 0

3 years ago

Danny's Bike Shop sells a certain model of racing bike for $550. The same bike can be bought at a competing shop for 7 percent l

AleksAgata [21]

Answer:

$511.5

Step-by-step explanation:

Given: Selling price of bike at Danny´s shop is $550

Bike is sold 7% less at competitor´s shop.

Lets find the discounted amount at Danny´s competitor shop.

∴ $\frac{7}{100} \times 550 = \$ 38.5$

Now, finding the cost of bike at Danny´s competitor.

Cost of bike at Danny´competitor= $(\textrm{Price at dannys shop - discount provided by competitor})$

Cost of bike at Danny´s competitor= $550-38.5= \$511.5$

∴ Cost of bike at Danny´s competitor is $511.5.

6 0

3 years ago

Researchers fed mice a specific amount of Toxaphene, a poisonous pesticide, and studied their nervous systems to find out why To

Mkey [24]

Answer:

a. The mean refractory period= 1.85 and the standard error = 0.06455

b. 90% confidence interval for the mean absolute refractory period for all mice when subjected to the same treatment = 1.6981, 2.0019

c. Yes, the data give good evidence to support this theory

Step-by-step explanation:

a. The table below shows the calculations:

X (X-mean)^2

1.7 0.0225

1.8 0.0025

1.9 0.0025

2.0 0.0225

Total 7.4 0.05

Sample size: n=4

The mean is: \bar{x} = \frac{7.4}{4} = 1.85

The sample standard deviation, s = \sqrt{\frac{\sum \left ( x-\bar{x} \right )^{2}}{n-1}}=0.1291

The standard error, se= \frac{s}{\sqrt{n}}=\frac{0.1291}{2} = 0.06455

b. Degree of freedom: df = n-1 = 3

Critical value of t for 90% confidence interval is: 2.3534

The confidence interval is \bar{x}\pm t_{c}se = 1.85\pm 2.3534\cdot 0.06455=1.85\pm 0.1519 = (1.6981, 2.0019)

c. The Hypotheses are:

H_{0}:\mu=1.3,H_{1}:\mu>1.3

So the test statistics will be

t=\frac{\bar{x}-\mu}{s/\sqrt{n}}=8.52

The p-value is: 0.0017

We reject the null hypothesis because p-value is less than 0.05 . This indicates that the data gave good evidence to support this theory.

4 0

3 years ago

Suppose that F is an inverse square force field below, where c is a constant.

Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

First of all we have,

$F(r) = \frac{cr}{|r|^{3} }$

and,

$r = xi+yj+zk$

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

$f(r) = - c /|r|$

That is,

$\nabla f = F$

For this case F is a conservative field and the line integral is independent of the path. Thus, defining $P_{1} = (x_{1}, y_{1}, z_{1})$ and $P_{2} = (x_{2}, y_{2}, z_{2})$ . So the amount of work on the movement of the object from P1 to P2 is,

$W=\int\limits_c {F} \, dr$

$W= f(P_{1}-P_{2})$

$W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}$

$W= c(\frac{1}{d1}-\frac{1}{d2} )$

2) The gravitational force field is given by,

$F(r) =-\frac{mMGr}{ |r|^3}$

The maximum distance from the earth to the sun is $1.52*10 ^ 8$ km and the minimum distance is $1.47*10 ^ 8$ km. The mass values of the bodies are given by m = $5.97*10 ^ {24}$ kg, M = $1.99 *19 ^ {30}$ kg and the constant G is $6.67 * 10 ^{ -11 }$ $\frac{Nm ^ 2}{kg^2}$