Question

If 3x + 2y = 8 and x is twice the value of y, what is the value of x -y?

Answer 1

Answer: $x-y = 1$

Step-by-step explanation:

Given:

$3x + 2y = 8$

since x is twice the value of y , this means that :

$x = 2y$  .......................... **

we will the substitute it into the main equation , that is we will substitute 2y in place of x. so the equation becomes :

$3(2y) + 2y = 8$

$6y + 2y = 8$

$8y = 8$

divide through by 8

$y = 1$

substitute y = 1 into equation ** , that is

$x = 2(1)$

$x = 2$

this means that :

$x = 2$ and $y = 1$ , so

$x - y = 2 -1$

$x-y = 1$

Answer 2

Answer:

1

Step-by-step explanation:

3x+2y=8          

x=2y

3(2y)+2y=8

6y+2y=8

8y=8

y=1

x=2(1)

x=2

x-1=2-1

x-y=1