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nalin [4]
3 years ago
13

If 3x + 2y = 8 and x is twice the value of y, what is the value of x -y?

Mathematics
2 answers:
tatyana61 [14]3 years ago
6 0

Answer: x-y = 1

Step-by-step explanation:

Given:

3x + 2y = 8

since x is twice the value of y , this means that :

x = 2y  .......................... **

we will the substitute it into the main equation , that is we will substitute 2y in place of x. so the equation becomes :

3(2y) + 2y = 8

6y + 2y = 8

8y = 8

divide through by 8

y = 1

substitute y = 1 into equation ** , that is

x = 2(1)

x = 2

this means that :

x = 2 and y = 1 , so

x - y = 2 -1

x-y = 1

Galina-37 [17]3 years ago
3 0

Answer:

1

Step-by-step explanation:

3x+2y=8          

x=2y

3(2y)+2y=8

6y+2y=8

8y=8

y=1

x=2(1)

x=2

x-1=2-1

x-y=1

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