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notka56 [123]
3 years ago
9

Which polynomial identity will prove that 64+27=91

Mathematics
2 answers:
Reptile [31]3 years ago
8 0

Answer:

Sum of cubes

Step-by-step explanation:

Naddik [55]3 years ago
7 0
Add 64 and 27 and you will get 91 So the problem will read: 64+27=91 91=91
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An integer is three more than another integer. Twice the larger integer is two less
Amiraneli [1.4K]

Answer:

The integers are 4 and 7 or -2 and 1.

Step-by-step explanation:

You can make a system of equations with the description of the two integers.

1. x = y + 3

2. 2x + 2 = y^2

The simplest and the fastest way to solve this system in this case is substitution. You can substitute x for y + 3 in the second equation.

1. x = y + 3

2. 2(y + 3) + 2 = y^2

Now simplify and solve the second one. For convenience, I will just disregard the first equation for now.

2y + 6 + 2 = y^2

y^2 - 2y - 8 = 0

You can factor this equation to solve for y.

(y - 4) (y + 2) = 0

y = 4, y = -2

Now we can substitute the value of y for x in the first equation.

x = 7, x = 1

3 0
3 years ago
Simplify -6x(9-12) ??
olga55 [171]
18x. Is your answer. :)
6 0
3 years ago
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andrew-mc [135]

Answer:

Answers below

Step-by-step explanation:

1)  4 (x+4)

2) 4x + 16

3) 2x+8

4) 2x+8

5) 3x+9

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3 years ago
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15 billion in numerals?
Leokris [45]
A billion has 9 zeros. So
15,000,000,000
:)
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LUCKY_DIMON [66]
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