1) No; you are incorrect. "0" is NOT a solution.
Plug in "0" for "x" ;
8*0² + 23 =? 823? ;
8*0 + 23 =? 823? ;
0 + 23 = ? 823 ? ; No! ; "0 + 23 = 23 " ; NOT "823" .
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2) The answers: x = 10, -10 ; or, write as: x = ± 10 .
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To solve:
GIven: 8x² + 23 = 823 ;
Subtract "23" from EACH SIDE of the equation:
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8x² + 23 - 23 = 823 - 23 ;
to get:
8x² = 800 ;
Now, divide EACH SIDE of the equation by "8" ;
8x² / 8 = 800 / 8 ;
to get: x² = 100 ;
Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
√(x²) = √(100) ;
x = <span>± 10 .
The answers: x = 10, -10 ; or, write as: x = </span><span>± 10 .
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A negative scale factor inverts the original image and scales it to what the number is.
An expansion means the image would get bigger.
For an image to get bigger the scale factor needs be be greater than 1.
-2 means the image would increase in size and be inverted.
2 means the image would increase in size.
The two correct scale factors are -2 and 2.
Answer:
I believe the answer is 0.3
$4s+$10a=$4,500 I’m pretty sure that is right? :)
Answer:
3a² - 13a - 10
Step-by-step explanation:
(a - 5) (3a +2) = a*3a +2*a -5*3a -5*2 = 3a² + 2a - 15a - 10 = 3a² - 13a - 10
