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meriva
3 years ago
14

Find all possible solutions for the following equation x²+7x+63=63

Mathematics
2 answers:
Ugo [173]3 years ago
8 0

Answer:

Step-by-step explanation:

X^2+7x+63=63

<=> x^2+7x=63-63=0

<=> X(x+7)=0

<=> x1=0

X2=-7

iVinArrow [24]3 years ago
4 0

Answer:

0 or -7

Step-by-step explanation:

     x² + 7x + 63 = 63

⇔ x² + 7x + 63 - 63 = 0

⇔ x² + 7x = 0

⇔ x(x + 7) = 0

So either:  x = 0

            or x + 7 = 0 ⇔ x = -7

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What is the equation of the line that passes through points (-3, 0.5) and (3, -0.5)
marissa [1.9K]

Answer:

y = (-1/6)x

Step-by-step explanation:

As we move from  (-3, 0.5) to (3, -0.5), x increases by 6 and y decreases by 1.

Hence, the slope of this line is m = rise / run = -1/6.

Starting with the slope-intercept form of the equation of a straight line, we have:

y = mx + b.  We substitute 0.5 for y, -3 for x and -1/6 for m, obtaining:

0.5 = (-1/6)(-3) - b, or:

0.5 = 0.5 - b.  Then b = 0, and the desired equation is

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3 years ago
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2) A fair coin was tossed 75 times. The coin landed on Heads 42 times and Tails 33 times. What is the experimental probability o
coldgirl [10]

Answer:

\frac{11}{25}

Step-by-step explanation:

In the experiment that was conducted the coin was tossed a total of 75 times and out of those times it only landed on tails 33 times. Therefore the experimental probability of the coin landing on tails can be calculated by the dividing the times it landed on tails by the total number of times it was tossed. Like so...

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This fraction can also be simplified to its simplest form of \frac{11}{25} which is obtained by dividing both the numerator and denominator by 3

5 0
3 years ago
There are 527 pencils,646 erasers,748 sharpeners . these are to be put in separate packets containing the same no. of items. fin
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To \; find \; the \; maximum \; number \; of \; items \; possible \; in each \; packet,\\we \; need \; to \; find \; the \; Greatest \; Common \; Factor\\ \; of \; 527 \; Pencils, \; 646 \; erasers \; and \; 748 \; sharpeners.\\\\We \; need \; to \; list \; the \; Factors \; of \; each \; number \; as \; given \; below\\ \; and \; identify \; the \; greatest \; common \; factor.

The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.

Conclusion: \\There \; will \; 31 \; Pencils, \; 38 \; Erasers,\\ \; and \; 44 \; Sharpeners \; in \; each \; of \; SEVENTEEN \; packet.

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3 years ago
How to find 9^4 without multiplying four 9s
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