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3 years ago

QUICK! TEN POINTS!! BRAINLIEST FOR WHOEVER GETS IT RIGHT!!!

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

7 0

Answer:

3rd

Step-by-step explanation:

ivann1987 [24]3 years ago

4 0

Answer:

Step-by-step explanation:

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For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

anastassius [24]

Answer:

15.62

Step-by-step explanation:

The Pythagorean theorem tells you the relation between the side lengths is ...

x^2 = 12^2 + 10^2 . . . the sum of squares of sides is the square of the hypotenuse

x^2 = 244

x = √244 ≈ 15.62

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2 years ago

a force of 50 lb act on an object at an angle of 45 degrees, a second force of 75 lb acts on the object at an angle of -30 degre

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3 years ago

In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 42.9%. the differen

fenix001 [56]

Let
x = number of common cars
y = number of suvs
we can write the following system of equations
x-y = 12
x = 1.429y
Solving the system we have
x-y = 12
1.429y-y = 12
and (1,429-1) = 12
y = (12) / (1,429-1) = 27.97202797
then,
x = 1429 * (27.97202797)
x = 39.97202797
answer
The number of suvs in the parking lot is 28

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3 years ago

Please help me I’m terrible at math

Katen [24]

Answer:

Moderate

Step-by-step explanation:

they are reversed

5 0

2 years ago

PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198

Elena-2011 [213]

The weight in 1980 is $\frac{4k}{5}$ kilograms

Solution:

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

To find: weight in 1980

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

The percentage increase is given by formula:

$\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100$

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

Substituting the values in formula,

$25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}$

Thus the weight in kilograms in 1980 is $\frac{4k}{5}$

7 0

3 years ago