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Ghella [55]
3 years ago
8

QUICK! TEN POINTS!! BRAINLIEST FOR WHOEVER GETS IT RIGHT!!!

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
7 0

Answer:

3rd

Step-by-step explanation:

ivann1987 [24]3 years ago
4 0

Answer:

15

Step-by-step explanation:

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For the following right triangle, find the side length x. Round your answer to the nearest hundredth.
anastassius [24]

Answer:

  15.62

Step-by-step explanation:

The Pythagorean theorem tells you the relation between the side lengths is ...

  x^2 = 12^2 + 10^2 . . . the sum of squares of sides is the square of the hypotenuse

  x^2 = 244

  x = √244 ≈ 15.62

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2 years ago
a force of 50 lb act on an object at an angle of 45 degrees, a second force of 75 lb acts on the object at an angle of -30 degre
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In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 42.9%. the differen
fenix001 [56]
Let
 x = number of common cars
 y = number of suvs
 we can write the following system of equations
 x-y = 12
 x = 1.429y
 Solving the system we have
 x-y = 12
 1.429y-y = 12
 and (1,429-1) = 12
 y = (12) / (1,429-1) = 27.97202797
 then,
 x = 1429 * (27.97202797)
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 answer
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6 0
3 years ago
Please help me I’m terrible at math
Katen [24]

Answer:

Moderate

Step-by-step explanation:

they are reversed

5 0
2 years ago
PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

7 0
3 years ago
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