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nika2105 [10]
3 years ago
8

What do you know about parallel slopes; perpendicular slopes?

Mathematics
1 answer:
sukhopar [10]3 years ago
7 0

Answer:

<em>Parallel slopes</em>: two lines that has the same slopes but have different y-intercept

<em>Perpendicular slope</em>: two lines that are negative reciprocals(common) of each other

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If tan theta = startfraction 11 over 60 endfraction, what is the value of cot theta?
Dennis_Churaev [7]

The value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

Given that trigonometric ratio:

tan\theta = \frac{11}{60}

<h3>What is the tangent of an angle?</h3>

The tangent of an angle is the ratio of the opposite side(to that angle) to the adjacent side(to that angle).

So, for the given problem

Opposite side to \theta = 11

Adjacent side to \theta = 60

So, cot \theta =\frac{AdjacentSide }{OppositeSide}

cot\theta =\frac{60}{11}

Therefore, the value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

To get more about trigonometric ratios visit:

brainly.com/question/24349828

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2 years ago
Plz awnser :) but explain i actually wanna know how to do this. long division, 1300÷15=?
chubhunter [2.5K]
(Divide) 1,300÷15=86.6666666667
6 0
3 years ago
In the diagram, figure I is a square, and figures II and III are equilateral triangles. What is the value of x?
baherus [9]

Answer:

f

Step-by-step explanation:

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3 years ago
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Solve the system.<br> 2x+y = 3<br> -2y = 14 - 6x
bezimeni [28]

Answer:

The solution is: (2, -1)

Step-by-step explanation:

First we rewrite the second system equation

-2y = 14 - 6x   →   6x-2y=14

Now we have the following system of equations:

2x+y = 3

6x-2y=14

To solve the system multiply the first equation by -3 and add it to the second equation

-6x+-3y = -9

6x-2y=14

--------------------------------------

0-5y=5

y=-1

Now we substitute the value of y in the first equation and solve for x

2x-1 = 3

2x= 4

x= 2

The solution is: (2, -1)

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3 years ago
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Determine the range of the following graph​
MakcuM [25]

Answer:It has to be more clear

Step-by-step explanation:

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