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irina1246 [14]
2 years ago
11

PLS HELP I WILL MARK BRAINLIEST

Mathematics
2 answers:
lorasvet [3.4K]2 years ago
5 0

Answer:

$31.44

Step-by-step explanation:

29.95 * .05 = 1.49

29.95 + 1.49= 31.44 (you add because its tax)

hope this helps! :)


Sonbull [250]2 years ago
5 0

Answer:

I believe the answer you're looking for is $27.25.

Step-by-step explanation:

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Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
2 years ago
17. Tonya's mother is 1.5 times as tall as
andrew-mc [135]

The question is incomplete:

17. Tonya's mother is 1.5 times as tall as  Tonya was when she was 6. How tall  is Tonya's mother? Use the correct  number of significant digits.

The image with the information about Tonya's height is attached.

Answer:

68 in.

Step-by-step explanation:

According to the information given, you can write the following expression:

x=1.5y

x=Tonya's mother height

y= Tony's height when she was 6

Also, you know from the table that Tonya's height when she was 6 was 45 in. and you can replace this value in the formula:

x=1.5*45

x=67.5

Because of this, the answer is that Tonya's mother height is 68 in.

3 0
3 years ago
How many possible passwords can you have if you can use numbers, letters, or capital letters but you must have at least one capi
belka [17]

Answer:

628 possible passwords.

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Use the number line to add the fraction. + + 1 1 7 3 -1 10 9 10 1 -1 10 4 5 3 5 Niat 1 2 + 1 5 N GIN 3 10 0 -1 3 10 1 10 + 1 2 +
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This is hard to understand , do u have a photo
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Troy's family is going to the beach for vacation. They plan to drive at the posted speed limit of 65 miles per hour and drive 5
Elena-2011 [213]
The answer is A) the number of miles
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