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sladkih [1.3K]
3 years ago
6

An unknown metal is dropped into 127 grams of water. The temperature of the water has been raised from 25OC to 28OC. Using the s

pecific heat of water found on page 54 determine the amount of heat gained by the water.
Chemistry
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

he amount of heat gained by the water is 1.59 kJ    

Explanation:

Relation between heat energy, specific heat and temperature change is as follows

Q = mCΔT

where,    Q or q = heat energy

             m = mass

             C = specific heat  =4.186J/g°C

ΔT = (28°C - 25°C) = 3°C

Now, putting the given values into the above formula as follows.

Q = mCΔT

= 127 × 4.186 × 3

= 1594.86 J or 1.59 kJ    

Therefore, we can conclude that the amount of heat gained by the water is 1.59 kJ    

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