If the point U is between points T and V, then the numerical length of TV is 29 units
<h3>How to determine the numerical length of segment TV?</h3>
From the question, we have the following lengths that can be used in our computation:
- Length TU = 18 units
- Length UV = 11 units
The above parameters and representations implies that the point U is between endpoints T and V
This also means that the length TV is longer than the other lengths TU and TV
So, we have the following length equation
TV = TU + UV
Substitute the known values in the above equation
So, we have the following equation
TV = 18 + 11
Evaluate the sum of the like terms in the above equation
So, we have the following equation
TV = 29
Hence, the numerical length of segment TV is 29 units
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<u>Possible question</u>
If tu = 18 and uv = 11 what is tv, if point u is between points t and v
One third is the written form.
Also, just a bit of extra information! The decimal of 1/3 is 0.33(recurring)
Rachel :)
L = rc
= 26.9 * 9*3.14 / 5
= 152.04 to nearest 1/100
I believe the answer is (-1,1) . The origin is the same as (0, 0) so I drew the line on a quick graph and if you are talking about distance, then the answer should be correct.
Hope this helped :)
Answer:
Step-by-step explanation:
6f^2 - 9f + 10 + 2f^2 + f - 3
8f^2 - 8f + 7
