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Irina18 [472]
3 years ago
15

The sum of three consecutive numbers is 84. What is the largest of these numbers?

Mathematics
2 answers:
geniusboy [140]3 years ago
8 0
27 +28 +29=84 so the number is 29
just olya [345]3 years ago
6 0
Let the numbers = x, x+1, x+2
It is given that, x + x+1 + x+2 = 84
3x + 3 = 84
3x = 84 - 3
3x = 81
x = 81/3
x = 27
Largest number, x+2 = 27+2 = 29

In short, Your Answer would be 29

Hope this helps!
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The entire pink figure has been transformed to create the new blue image. Describe the transformation that has taken place.
Leno4ka [110]

Answer:

D. (bottom right)

Step-by-step explanation:

If there is a line where y = x, that means that y and x can both equal 1, 2, 3, -1, -2, -3, etc. They are just always the same. This line, then, would pass through (just for example) (-4, -4) and (4, 4). If you reflect the pink figure across that line, you will get the blue figure. Hope this helps!

6 0
2 years ago
Angles X and Y are complementary. The measure of Angle Y is 55.5 degrees. What is the measure of Angle X?
mina [271]
Two angles are called complementary when their measures add to 90 degrees
8 0
3 years ago
How do u guys do a step by step explanation on this app sorry I’m new
sukhopar [10]

Answer:

Usually people don't give step by step explanations but you could explain how you solved it  for example

x=5

Step-by-step explanation:

and then show how you solved the equation "2x=10"

5 0
3 years ago
The area of a rectangle is 5/8 meter. The length of the garden is 1/5 meter. What is the width of the rectangle?
Afina-wow [57]

Width of rectangle is Width=\frac{25}{8} meters

Step-by-step explanation:

Area of rectangle = \frac{5}{8}

Length of garden = \frac{1}{5}

Width of rectangle = ?

Using the Formula:

Area = Length * Width

Putting values and finding width:

\frac{5}{8}=\frac{1}{5}*Width\\ Width=\frac{5}{8}\div\frac{1}{5}\\Width=\frac{5}{8}*\frac{5}{1}\\Width=\frac{25}{8} meters

So, width of rectangle is Width=\frac{25}{8} meters

Keywords: Area of rectangle

Learn more about Area of rectangle at:

  • brainly.com/question/12919591
  • brainly.com/question/6837543
  • brainly.com/question/6564657

#learnwithBrainly

8 0
2 years ago
A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

4 0
2 years ago
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