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Anastasy [175]
3 years ago
14

Find the value of x and y to the nearest tenth

Mathematics
1 answer:
Readme [11.4K]3 years ago
5 0
The value of 'x' is 24.2 and the value of 'y' is 46.5.

To solve this, we do the following steps.
<u>Step 1:</u> Divide 'y' into 2 parts, 'a' and 'b'. 'a' would be the lower leg of the 45°-45°-90° triangle, while 'b' is the lower leg of the 30°-60°-90° triangle.<em>
</em><u>Step 2:</u> Given the hypotenuse (34) of the 30°-60°-90° triangle, solve for 'b' using the cosine of 30°.
    cos30° = b/34 [adjacent over hypotenuse]
    b = 34cos30° [cross-multiply]
    b = 29.4
<u>Step 3:</u> Solve for the 90° leg (the side opposite the 30° angle) using the Pythagorean Theorem. We will name this leg "h" (cuz height).
     l² + l² = hyp²
     29.4² + h² = 34²
     h² = 1156 - 864.36
     √h² = √291.64
     h = 17.1
<u>Step 4:</u> Solve for 'x' by using the 45°-45°-90° triangle ratio (1:1:√2). √2 would be the hypotenuse of the 45°-45°-90° triangle, while 1 would be both congruent legs.     
  Side 'h' is one of the legs; side 'a' is the other. Since these legs are congruent, 'a' also measures 17.1. Now all we need to do is solve for 'x', which is our hypotenuse. To do this, we simply multiply the measure of side 'h' or 'a' by √2.
     x = 17.1 × √2
     x = 24.2
<u>Step 5:</u> Now that we got the value of 'x', solve for 'y' by adding the measures of sides 'a' and 'b' together.<em>
</em><u />     y = a + b
     y = 17.1 + 29.4
     y = 46.5

And there you have it! <em>Hope this helps.</em>
     <em>
</em>
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Step-by-step explanation:

Combine like terms

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A right cylinder has a radius of r inches and height of 2r inches.
Bess [88]

Answer:

the volume is 6.28r^{3}in^{3}

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, a cylinder.

Given data

Volume v =  ?

Radius r =  r in

Height h=   2r in

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we know that the expression for the volume of a cylinder is

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3 years ago
a rectangular pyramid has a volume of 190 cubic centimeters. Find two possible sets of measurements for the base area and height
DerKrebs [107]
<h3>One possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively</h3><h3>Other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively</h3>

<em><u>Solution:</u></em>

<em><u>The volume of rectangular pyramid is given as:</u></em>

Volume = \frac{1}{3} \times base\ area \times height

Given that,

<em><u>Rectangular pyramid has a volume of 190 cubic centimeters</u></em>

<em><u></u></em>190= \frac{1}{3} \times base\ area \times height<em><u></u></em>

<em><u>Substitute, base area = 570 and height = 1</u></em>

Then we get,

190 = \frac{1}{3} \times 570 \times 1\\\\190 = 190

Thus one possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively

<em><u>Substitute, base area = 285 and height = 2</u></em>

190 = \frac{1}{3} \times 285 \times 2\\\\190 = \frac{1}{3} \times 570\\\\190 = 190

Thus other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively

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