This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
Answer:
My answer would be 9 unit away
Step-by-step explanation:
becuase you can subtract 0 from -9
0 + -9 would equal -9
then 9 - (-9) = 0
so 9 is my answer
sorry if i am wrong
Answer:
B.
Step-by-step explanation:
When reflecting over the x-axis:
(x, y) (x, -y)
The y changes signs (+, -)
Answer:
i tried but i dont understand sorry
Step-by-step explanation: