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Sunny_sXe [5.5K]
3 years ago
15

Divide the polynomial 3x^4-2x^3+5x^2-3 by (x+1).​please give fast.

Mathematics
1 answer:
Dimas [21]3 years ago
4 0

Answer: The answer is: 3x^{3} -5x^{2} +10x -10 + {7}{x + 1}

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A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i
Setler79 [48]

Answer:

Part a) The slant height is 3\sqrt{2}\ units

Part b) The lateral area is equal to 54\sqrt{2}\ units^{2}

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

so

LA=6[\frac{1}{2}(b)(l)]

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

l^{2}=h^{2} +a^{2}

where

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we have

h=3\ units

a=3\ units

substitute

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l=3\sqrt{2}\ units

Part b) Find the lateral area

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we have

b=6\ units

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LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}

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