All categories

3 years ago

a photo graph measuring 8cm by 6cm is enlarged by a ratio of 11 : 4 what are the dimensions of new print ?

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

22cm and 16 1/2 cm is the answer

Write the ratio as a fraction and multiply with each dimension

You might be interested in

What is the solution to 3 x 2. 4 greater-than-or-equal-to 3. 0? x greater-than-or-equal-to 0. 2 x greater-than-or-equal-to 0. 6

IRINA_888 [86]

Answer:

express the following as a fraction and a ratio

6 0

2 years ago

How to find gain or loss % when the gain or loss % is not given

g100num [7]

Answer:

Gain = S.P - C.P

Loss =C.P - S.P

where, S.P equals spelling price

and C.P equals cost price

Step-by-step explanation:

Hope it helps

7 0

3 years ago

There are 2 pecks in one kenning there are 2 kennings in 1 bushel there are 8 bushels in1 quarter there are 5 quarters in 1 load

Delicious77 [7]

Answer:

yes 1 2 3

Step-by-step explanation:

7 0

3 years ago

Solve for the factual of (5!)

Lelu [443]

1×5 or 5×1 would be a factual of it

4 0

3 years ago

Find the general indefinite integral. (use c for the constant of integration. )

Vlada [557]

The indefinite integral will be $\int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)$

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0

2 years ago

a photo graph measuring 8cm by 6cm is enlarged by a ratio of 11 : 4 what are the dimensions of new print ?​

a photo graph measuring 8cm by 6cm is enlarged by a ratio of 11 : 4 what are the dimensions of new print ?