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Anastasy [175]
3 years ago
5

If $-2 < x \le 3,$ then find all possible values of $5x + 1.$ Give your answer in interval notation. We suggest you study Sec

tion 9.1 if you find this problem difficult.
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

-2<x≤3

multiply by 5

-10<5x≤15

add 1

-9<5x+1≤16

(5x+1)∈(-9,16]

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For the given expression, use the Commutative Property of Addition to enter an equivalent expression.
Triss [41]

Answer:

x+19=19+x

Step-by-step explanation:

3 0
3 years ago
6. (-2, 1) and (0,3) Slope= Equation=​<br><br>answer both please
olga_2 [115]

Answer:

(-2, 1) and (0, 3) has the slope of m = 1 and the equation is y = x + 3

(0, -2) and (3, -5) has the slope of m = 1 and the equation is y = -x - 2

Step-by-step explanation:

Hope this helps!

3 0
3 years ago
Please help me I will give 30 points
LuckyWell [14K]

Answer:

a, c, & d

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Is​ f(x) continuous at x equals 4​? Why or why​ not? A. ​No, f(x) is not continuous at x equals 4 because ModifyingBelow lim Wit
soldier1979 [14.2K]

<u>Corrected Question</u>

Is the function given by:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right ​

continuous at x=4​? Why or why​ not? Choose the correct answer below.

Answer:

(D) ​Yes, f(x) is continuous at x = 4 because Lim_{x \to 4}f(x)=f(4)

Step-by-step explanation:

Given the function:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right

A function to be continuous  at some value c in its domain if the following condition holds:

  • f(c) exists and is defined.
  • Lim_{x \to c}$ f(x) exists.
  • f(c)=Lim_{x \to c}$ f(x)

At x=4

  • f(4)=\dfrac{1}{4}*4+1=2
  • Lim_{x \to 4}f(x)=2

Therefore: Lim_{x \to 4}f(x)=f(4)=2

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0
3 years ago
Two trains leave the same station at the same time, but are headed in opposite directions. One train travels at 70 mph and the o
uranmaximum [27]

Let

x--------> the time in hours

y-------> the distance in miles

we know that

The speed is equal to

Speed=\frac{distance}{time}

in this problem

Speed=\frac{y}{x}

y=(Speed)*x

<u>Equation First Train</u>

y1=70x

<u>Equation Second Train</u>

y2=80x

y1+y2=600\ miles ---------> equation 1

Substitute the values of y1 and y2 in the equation 1

70x+80x=600

Solve for x

150x=600

x=4\ hours

therefore

<u>the answer is</u>

4\ hours

4 0
3 years ago
Read 2 more answers
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