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Gala2k [10]
2 years ago
14

How can -6 1/3 be expressed as the sum of it's integer and fractional parts?

Mathematics
2 answers:
kumpel [21]2 years ago
7 0

Answer:

bottom left: -6 + (-1/3)

Step-by-step explanation:

hope this helps :)

Minchanka [31]2 years ago
5 0
It’s -6 + (-1/3) I think :)
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A model of a famous statue is 1 and one fourth inches tall. The actual statue is 6 and two thirds feet tall. What is the ratio o
Studentka2010 [4]
First, you need to convert 5 1/4 feet to inches. 5.25 x 12 = 63 inches. The ratio of the height of the model to the height of the actual statue in simplest form is 1/42. I don't know if this is correct but I hope this helps you in any way.
5 0
3 years ago
A ramp leading into a building makes a 15o angle with the ground. the end of the ramp is 10 feet from the base of the building.
Oksanka [162]
We are tasked to solved for the length of the ramp having an inclination of 15 degrees with the ground and 10 feet from the end of the ramp to the base of the building of the ground. Using trigonometric properties, we have a formula given an angle and the its opposite sides which is,
sin(Angle)=opposite/hypothenuse
hypothenuse would be the distance or the length of the ramp.
so we have,
sin(15)=10/hypothenuse
Cross-multiply, we have,
hypothenuse=10/sin(15)
using scientific calculator having a DEG mode,
hypothenuse=38.63703
Rounding of in nearest tenth we get,
hypothenuse=38.6 ft
Therefore, the ramp is 38.6 ft long
3 0
3 years ago
Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a
spin [16.1K]

Answer:

Mean = 68.9

s^2 =18.1 --- Variance

Step-by-step explanation:

Given

\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5

For 59 - 66

x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5

For 67 - 74

x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5

For 75 - 82

x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5

For 83 - 90

x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5

So, the table becomes:

\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

The mean is then calculated as:

Mean = \frac{\sum fx}{\sum f}

Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}

Mean = \frac{2547.5}{37}

Mean = 68.9 -- approximated

Solving (b): The sample variance:

This is calculated as:

s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}

So, we have:

s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}

s^2 =\frac{652.8}{36}

s^2 =18.1 -- approximated

5 0
2 years ago
4(x+5)+4x+8
kvasek [131]
B.) 8(x+4) is the best choice
6 0
3 years ago
Read 2 more answers
Write 0.21..... as a fraction in simplest form
kondor19780726 [428]
.21 as a fraction would be 21/100
8 0
2 years ago
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