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3 years ago

What are the slope and the y-intercept of the line shown in the graph?

Mathematics

1 answer:

vladimir1956 [14]3 years ago

7 0

Answer:

Step-by-step explanation:

The y intercept is where the line crosses the Y (vertical) axis. In this case, it happens at y=2

The slope is the rate of change. For every 1 space it moves on the horizontal axis, it moves 3 vertical spaces. It is going down, so it is -3

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An arithmetic sequence "a" starts with 84, 77 define "a" recursively

sweet [91]

Answer:

First, let's define an arithmetic sequence:

In an arithmetic sequence, the difference between any two consecutive terms is always the same.

Then we can write it in a general way as:

aₙ = a₁ + (n - 1)*d

where:

aₙ is the n-th term of the sequence.

d is the constant difference between two consecutive terms.

a₁ is the initial term of our sequence.

Now in this case we know that the first terms of our sequence are:

84, 77, ...

Then we know the initial term of our sequence:

a₁ = 84.

And the value of d can be calculated as:

d = a₂ - a₁ = 77 - 84 = -7

Then the general way of writing this sequence is:

aₙ = 84 + (n - 1)*(-7)

And the recursion relation is:

aₙ = aₙ₋₁ - 7

So for the n-th term, we must subtract 7 of the previous term.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B25-10%5Csqrt%7B3%7D%2B3%20%7D" id="TexFormula1" title="\sqrt{25-10\sqrt{3}+3 }" alt=

Varvara68 [4.7K]

Here is your answer: )

6 0

2 years ago

Someone please help me

Keith_Richards [23]

Answer:

Step-by-step explanation:

8 0

3 years ago

The formula κ(x)= f′′(x) 1+f′(x)23/2 expresses the curvature of a twice-differentiable plane curve as a function of x. Use thi

Katyanochek1 [597]

Answer:

K(x) = $\frac{-10}{[1 + (-10x)^2]^{\frac{3}{2} } }$ ( curvature function)

Step-by-step explanation:

considering the Given function

F(x) = $-5x^2$

first Determine the value of F'(x)

F'(x) = $\frac{d(-5x^2)}{dy}$

F'(x) = -10x

next we Determine the value of F"(x)

F"(x) = $\frac{d(-10x)}{dy}$

F" (x) = -10

To find the curvature function we have to insert the values above into the given formula

K(x) $= \frac{|f"(x)|}{[1 +( f'(x)^2)]^{\frac{3}{2} } }$

K(x) = $\frac{-10}{[1 + (-10x)^2]^{\frac{3}{2} } }$ ( curvature function)

6 0

3 years ago

Urgent please help .On a piece of graph paper, graph y+2<-2/3x+4

Serjik [45]

Take a look at the function $y+2=- \frac{2}{3}x+4$ . You can simplify it to $y=- \frac{2}{3}x+2$ . If x=0, then y=2 and when y=0, x=3. You obtain two points (0,2) and (3,0) that lie on the line $y+2=- \frac{2}{3}x+4$ .

Since $y+2\le - \frac{2}{3}x+4$ , the line $y+2=- \frac{2}{3}x+4$ should belong to the shaded area.

Now take point (0,0). Since $0+2\le- \frac{2}{3}\cdot 0+4$ , you can conclude that point (0,0) belongs to the shaded area.Using all these thoughts, you can make a conclusion that the correct choice is B.

8 0

3 years ago